39. The impedance of a transmission line is 30 ohm. What is the per unit impedance of 115 kv and 100 MVA base? O 0.18 O 0.05 O 0.03 O 0.22
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- The reactance of a generator is given as 0.1 pu based on the generator of 17 KV, 300 MVA. Determine the pu reactance on a base of 17 KV, 250 MVA. New pu reactance is.......The p.u. impedance value of an alternator corresponding to base values of 13.2 kV and 30 MVA is 0.2 p.u. Then the p.u. impedance value of an alternator for the new base values of 13.8 kV and 50 MVA is......A 30 MVA, 11 kV generator has a reactance of 0.10p.u.on its own base. Determine the per-unit reactance when referred to base kVA of 50,000 kVA and base kV of 33 kV.
- The reactance of a generator is given as 0.25 per-unit based on the generator’s of 18 kV, 500 MVA. Find its per-unit reactance on a base of 20 kV, 100 MVA. a. 0.0505 b. 0.0605 c. 0.0405 d. 0.0606The actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power is O 4000 VA O 8000 VA O 6000 VA O 2000 VAIn the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generator is connected in star with its star points grounded. The per unit impedances of each element on a 40 MVA base are given in Table 1 and the voltage levels are given in Table 2. Z [p.u.] 0 2 tööt Generator 0.01 +j0.08 p.u. L Figure 1: A section of the distribution system Transformer T1 Line V BASE [KV] 0.04 + j 0.03 + j 0.15000000000000002 0.06000000000000000 Generator Table 1: Sequence impedances (p.u. on 40 MVA base) 3 T2 181. Line 3 10 Table 2: Voltage bases (kV) Load 1 Transformer T2 Load Current A load current of 11.316 kA is flowing with a lagging power factor of 90 %. Convert this to a current vector in per-unit. IL = 0.04 + j 0.06000000000000000
- For the system as shown in the following figure, convert the components to same base voltage and apparent power, by choosing 100 kVA as the base kVA and 2000 V as the base voltage for the generators. Redraw the single line diagram with the new per unit values. 15 KVA 2000 V Z=j0.3 pu 25 KVA 2000 V Z=j0.15 pu G1 G2 35 KVA 2000/8000 V Z=j0.2 pu Z=30+j100 Z=60+j120 pu O pu leee 35 KVA 8000/2000 V Z=j0.3 pu 35 kVA 2000/8000 V Z=j0.25 pu G3 10 KVA 2000V Z=j0.35 pu M 30 KVA 2000 VThe actual impedance of a load is 30 OHM. The per-unit impedance of the load is 0.5 pu when Base Voltage is 600 V and Base Power is O 6000 VA O 2000 VA O 4000 VA 8000 VAThe actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power Is O 4000 VA CO 8000 VA O 6000 VÀ O 2000 VA
- The one-line diagram of a three-phase system is shown in Figure 1. By selecting a common based of 90 MVA and 32.75 kV on the generator bus, all impedances including the load impedance in per-unit are as follows: XG (new) = j0.1421 p.u XT1 (new) = j0.1219 p.u XT2 (new) = j0.1219 p.u ZOH = 0.0016 +j 0.0083 p.u Хм пеw) 3D j0.247 р.u ZLoad = 2.2759+ j1.2306 p.u T1 T2 90 MVA Motor 90 MVA 55 MVA 33/275 kV 275/11kV 10.95 kV XT=12% Xr3=12% Xx=15% Generator 95 MVA M 32.75 kV Xg=15% 2 x OH Line 138 km R = 0.01 ohm/km X = 0.05 ohm/km Load 35 MVA 10.95 kV 0.88 pf lagging Figure 1 Note: Region 1 = Generator bus Region 2 = Transmission Lines busses Region 3 = Load Bus If the motor operates at full load 0.88 power factor lagging at a terminal voltage 10.95 kV, determine the voltage at the generator bus bar.The rating of generator is expressed in terms of kVA Select one: True FalseX₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O oto