A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter19: Temperature, Thermal Expansion And Gas Laws
Section: Chapter Questions
Problem 39PQ
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A rubber band is under tension in equilibrium, modeled by the equation
t
1 = AT (12 - 1/1)
\x2
With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band
without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as
constant.
(a) Solve the following as a function of x and T
(JE)
(i)
(ii) (bcx)T (iii) cx(x,T)
(iv) E(x,T) and
(v) S(x,T)
Where E is the energy and S is entropy
(b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?
Transcribed Image Text:A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?
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