Concept explainers
The sole of a man’s size-10 shoe is around 11.0 in. by 4.00 in. Determine the gauge pressure under the feet of a 200-lb man standing upright. Give your answer in both
The gauge pressure under the feet of a 200-lb man standing upright if the size of the man’s sole is around 11.0 in. by 4.00 in.
Answer to Problem 26SP
Solution:
Explanation of Solution
Given data:
The weight of the person is
The length of each foot is
The breadth of each foot is
Formula used:
Write the expression for pressure exerted by the shoe:
Here,
Write the expression of the area of one shoe:
Here,
Explanation:
Recall the expression of the area of one shoe:
Here,
Substitute
Here, the force applied by both feet is equal to the weight of the person which is equally divided on both feet. Hence, the force on one foot will be
Thus, the expression of gauge pressure under the feet of the man standing upright will be:
Here,
Substitute
Convert the pressure from
Conclusion:
Therefore, the gauge pressure under the feet of a 200-lb man standing upright is
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Chapter 13 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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