Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 35Q
To determine
The benefits of using light year as the unit of distance by astronomers.
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Raising a number in scientific notation to a power is easy:
(5 x 105)² = (5)² x (105)² = 5 x 5 x 105 x 105 = 25 x 10(5 × 2) = 25 x 1010 = 2.5 x 101¹1
Keeping this in mind, what is the volume of the sun in km³? The radius of the sun is about 7 x 105 km, and the volume of a sphere is 4/3 x Pi x R³. (Use 3.14 for Pi, and enter your answer with two decimal places).
km³
3
What is the average density of the Sun? Density = mass / volume. The mass of the sun is 2.0x10³0 kg.
kg/km³
The nearest star to our sun is Proxima Centauri, at a distance of 4.3 light-years from the Sun. A light-year is the distance that light travels in one year (365 days). How far away, in kilometers, is Proxima Centauri from the Sun?Express your answer using two significant figures.
How do you figure this out??
Chapter 1 Solutions
Universe
Ch. 1 - Prob. 1CCCh. 1 - Prob. 2CCCh. 1 - Prob. 3CCCh. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7Q
Ch. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10QCh. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 14QCh. 1 - Prob. 15QCh. 1 - Prob. 16QCh. 1 - Prob. 17QCh. 1 - Prob. 18QCh. 1 - Prob. 19QCh. 1 - Prob. 20QCh. 1 - Prob. 21QCh. 1 - Prob. 22QCh. 1 - Prob. 23QCh. 1 - Prob. 24QCh. 1 - Prob. 25QCh. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - Prob. 31QCh. 1 - Prob. 32QCh. 1 - Prob. 33QCh. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42QCh. 1 - Prob. 43QCh. 1 - Prob. 44Q
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- Ex. 10 : What would have be the duration of the year if the distance between earth and sun were half the present distance ?arrow_forwardHow can I get the solution and answers to this problem?arrow_forwardConsider a star at a distance of 100 light years from the Earth and is moving relative to the Earth at a constant velocity of 70000 km/hr perpendicular to its line of sight from the Earth. What is the change of its angular position on our sky when viewed by us now and by the ancient Egyptian 6000 years ago? Ignore all other effect, e.g., the axial precession of the Earth. 1. (A) 0.24 arcsecond (В) 13 arcminutes (C) 0.5 degree (D) 2.6 degrees (E) 5.0 degreesarrow_forward
- A planet's speed in orbit is given by V = (30 km/s)[(2/r)-(1/a)]0.5 where V is the planet's velocity, r is the distance in AU's from the Sun at that instant, and a is the semimajor axis of its orbit. Calculate the Earth's velocity in its orbit (assume it is circular): What is the velocity of Mars at a distance of 1.41 AU from the Sun? What is the spacecraft's velocity when it is 1 AU from the Sun (after launch from the Earth)? What additional velocity does the launch burn have to give to the spacecraft? (i.e. What is the difference between the Earth's velocity and the velocity the spacecraft needs to have?) How fast will the spacecraft be traveling when it reaches Mars? Does the spacecraft need to gain or lose velocity to go into the same orbit as Mars?arrow_forwardWhich unit of length would most likely be used to measure the distance from Earth to stars other than the sun? O Meter O Light-year O Kilometer O Astronomical unit 24 25 26 27 28arrow_forwardGalileos telescope showed him that Venus has a large angular diameter (61 arc seconds) when it is a crescent and a small angular diameter (10 arc seconds) when it is nearly full. Use the small-angle formula to find the ratio of its maximum to minimum distance from Earth. Is this ratio compatible with the Ptolemaic universe shown in Figure 3b of the Chapter 4 Concept Art: An Ancient Model of the Universe?arrow_forward
- The distance from the Sun to the nearest star is about 4 1016 m. The Milky Way galaxy (Fig. P1.31) is roughly a disk of diameter 1021 in and thickness 1019 m. Find the order of magnitude of the number of stars in the Milky Way. Assume the distance between the Sun and our nearest neighbor is typical. Figure P1.31 The Milky Way galaxy.arrow_forwardThe diameter of Earth across the equator is 7928 miles. If a mile equals 1.609 km. what is Earths diameter in kilometers? In centimeters?arrow_forwardWhy did early human cultures observe astronomical phenomena? Was it for scientific research?arrow_forward
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