The Science and Engineering of Materials (MindTap Course List)
7th Edition
ISBN: 9781305076761
Author: Donald R. Askeland, Wendelin J. Wright
Publisher: Cengage Learning
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Textbook Question
Chapter 12, Problem 12.76P
Compare the interlamellar spacing and the yield strength when a eutectoid steel is isothermally transformed to pearlite at
(a) 700°C: and
(b) 600°C.
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If a eutectoid steel sample is heated to 800°C and then quenched in a cold-water bath then
what would be the possible microstructure? Draw the microstructure and label it.
A 0.25% C hypoeutectoid plain-carbon steel is slowly cooled from 950°C to a temperature just slightly below 723°C.(a) Calculate the weight percent proeutectoid ferrite in the steel.(b) Calculate the weight percent eutectoid ferrite and weight percent eutectoid cementite in the steel.
A nitriding heat treatment of a BCC steel normally requires 2 h at 600 °C. What temperature would be required to reduce the heat treatment time to 1 h?(Q =76570 J/mol, Do =0.0047x10- 4 m2/s)
and the last one. thanks for ur helping.
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- (11.10) Suppose that a steel of eutectoid composi- tion is cooled to 550°C (1020°F) from 760°C(1400°F) in less than 0.5 s and held at this temperature. (a) How long will it take for the austenite- to pearlite reaction to go to 50% comple- ton? To 100% completion? (b) Estimate the hardness of the alloy that has completely transformed to pearlite? 11.12) Briefly cite the differences between pearl- rp. bainite, and spheroidite relative to crostructure and mechanical properties?arrow_forwardProblem Isothermal transformation diagram for an iron-carbon alloy of eutectoid com- position (0.76 wt% C). Assume that the specimen begins at 760°C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure. Sketch the following treatment on the figure: Rapidly cool to 575°C, hold for 20s, rapidly cool to 350°C, hold for 100s, then quench to room temperature. Specify microcon- tituents with percentage. 1. Sketch the following treatment on the figure: rapidly cool to 600°C, hold 4s, rapidly cool to 450°C, hold for 108, and rapidly cool to room temperature. Specify microcontituents with percentage. 3. ( Sketch the following treatment on the figure: rapidly cool to 450°C, hold 10s, rapidly cool to room temperature, heat to 680°C, hold 30hrs, and cool to room temperature. Specify microcontituents with percentage. Temperature (°C) 4. (a) 0.2 wt% C with spheroidite (b) 0.2 wt% C with fine pearlite 800 (c) 0.76 wt% C with fine…arrow_forwardA 1070 steel is heated to the austenite region and air cooled. Calculate the hardness of this steel. Sketch the final microstructure...arrow_forward
- If a 0.80 percent plain carbon steel is austenitized (heated to a read heat) and quenched in water to room temperatures so that the cooling curve does not cut into the “nose” of the I-T diagram, what will the resultant microstructure be?arrow_forwardA nitriding heat treatment of a BCC steel normally requires 2 h at 600 °C. What temperature would be required to reduce the heat treatment time to 1 h?(Q =76570 J/mol, Do =0.0047x10- 4 m2/s)arrow_forward(b) Figure Q4 (b) displays the time-temperature cooling paths for a 1080 steel on an isothermal transformation diagram. Start with the steels in the austenitic condition at time = 0 and 850°C. Interpret the final microstructures that will be obtained for paths (i, ii and iii) shown in the figure. 700 600 500 400 300 (iii) Ms 200 (i) (ii) Mf Figure Q4 (b)arrow_forward
- Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. Cooling rate at 700°C (°C/sec) 300 150 011/3 55 100 600 Bar diameter (mm) 80 60 40 20 0 OLL 0 0 ww 25 12.5 8 5 S -------------- M-R 10 3/4-R Agitated oil 15 20 1/4 3/4 Distance from quenched end. De (Jominy distance) 5.5 4 3 Bar diameter (in.) 0 25 mm 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R mid-radius) 65 60 55 50 45 40 35 30 25 20 15 10 0 10 1 20 Distance from quenched end (mm) 5140 1 30 L 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 4340 40 9840 4140 8640 50arrow_forward1.0% of euctectoid carbon steel was slowly cooled from 900C to a temperature just below 723C 1. Calculate the wt% of cementite at the proeutectoid cementite 2. Calculate the amount of euctectoid cementitearrow_forwardWhat is the% C ratio of two different steels with 80% and equal austenite content at 724 C? please explain how to calculatearrow_forward
- A 609 g eutectoid steel ( about 0.8%C) is heated to 1,002 C and cooled slowly through the eutectorid temperature. This results in the formation of cementite Fe3C (6.67%C) and ferrite (0.025%C). Calculate the number of grams of cementite that form in the steel.arrow_forwardExplain the phases shown in the attached image of a stress strain cureve for 0.15% carbon steelarrow_forwardjnd Retained austenite represents a large problem in hardened steel, because ....*. ..........arrow_forward
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