Which of the following expressions create an empty tuple? O tuple() tuple([) O tuple({}) O tuple()) O (None) tuple(0)
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- # define stemmer functionstemmer = SnowballStemmer('english') # tokenise datatokeniser = TreebankWordTokenizer()tokens = tokeniser.tokenize(data) # define lemmatiserlemmatizer = WordNetLemmatizer() # bag of wordsdef bag_of_words_count(words, word_dict={}): """ this function takes in a list of words and returns a dictionary with each word as a key, and the value represents the number of times that word appeared""" for word in words: if word in word_dict.keys(): word_dict[word] += 1 else: word_dict[word] = 1 return word_dict # remove stopwordstokens_less_stopwords = [word for word in tokens if word not in stopwords.words('english')] # create bag of wordsbag_of_words = bag_of_words_count(tokens_less_stopwords) Use the stemmer and lemmatizer functions (defined in the cells above) from the relevant library to find the stem and lemma of the nth word in the token list. Function Specifications: Should take a list as input and…tonquage accepting any no.fa's } prite a P.E for the and b's over, & = {a,b?f : {1, 2, 3} ® {a, b, c, d} f(1) = c f(2) = b f(3) = a g : {a, b, c, d} ® {x, y, z} g(a) = y g(b) = x g(c) = x g(d) = z Find the composition gof
- A tuple that contains elements is true. True or false? In Python.Find the body for: def contains_no_lowercase_vowels(phrase: str) -> bool: """Return True iff (if and only if) phrase does not contain any lowercase vowels. >>> contains_no_lowercase_vowels('syzygy') True >>> contains_no_lowercase_vowels('e') False >>> contains_no_lowercase_vowels('abc') False """Function 1: draw_subregion Complete the implementation of draw_subregion. This function has the following parameters: my_turtle: A turtle object (which will do the drawing) polygon_points: A list of (x, y) points (i.e. a list of tuples) that defines the points of a polygon. This function should make the turtle draw the polygon given by the points. Make sure that you lift your pen before heading to the first point. You should also make sure you return to the very first point at the end (i.e. you will go to the first point in the list two times: once at the beginning, and once at the end). Language Python
- Problem Description Gary being the smartest guy in the town is a friend of you. He challenges you with an interesting problem. He gives you a number A and asks you to find the number of "actual" greater pairs till A. An actual greater pair(a, b) means that it should hold following conditions • 0 <=a<b<= n • Sum of digits of a < Sum of digits of b The number A is given you in form of a string as it can be very huge! Return the number of actual greater pairs with above conditions modulo 1e9+7. Problem Constraints 1 <= A < 10100Examine the code below: t = (1,) Rewrite the line of code to unpack the tuple.Doctor -signature:String -doctorID:int - medicine:Arraylist +Doctor(signature:String,doctorID:int) +PrescribeMedicine():void + salary () +checkRecords():void Medicine Pharmacist -medName:String -startTime:int -dosage :int -endTime:int -date_prescribed:int - medicine:Arraylist +Medicine(medName:String,-dosage :int,date_prescribed:int) +Pharmacist (startTime:int,endTime:int) +checkForConflict():double +confirm_prescription():String +getStartTime():int +getEndTime():int +setStartTime(time:int):void +setEndTime(time1:int).void
- Q2 Let L = {b, abb, bba}. Which of the following strings is not a member of L*? ΟΛ O bababb bbbaabb O bbbbababbabbRegular expression to NFA to DFA conversion: Describes the process of taking a unique regular expression, converting that regular expression to an NFA, then converting the NFA into a DFA. Your regular expression must have at minimum two union, two concatenation, and two Kleene star operations. As followed, concatenations of single charaters can be condensed. Your regular expression cannot be a solved problem from any book. You should describe the regular expression with both processes to convert the regular expression to an NFA and the conversion of that NFA into a DFA.def is_balanced(root): return __is_balanced_recursive(root) def __is_balanced_recursive(root): """ O(N) solution """ return -1 != __get_depth(root) def __get_depth(root): """ return 0 if unbalanced else depth + 1 """ if root is None: return 0 left = __get_depth(root.left) right = __get_depth(root.right) if abs(left-right) > 1 or -1 in [left, right]: return -1 return 1 + max(left, right) # def is_balanced(root):# """# O(N^2) solution# """# left = max_height(root.left)# right = max_height(root.right)# return abs(left-right) <= 1 and is_balanced(root.left) and# is_balanced(root.right) # def max_height(root):# if root is None:.