Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C

Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying the function accordingly. Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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5.9: Functions: Common errors
CHALLENGE
5.9.1: Function errors: Copying one function to create another.
АCTIVITY
Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and
modifying the function accordingly.
Sample output with input: 283.15
10.0 C is 283.15 K
283.15 K is 10.0 C
247772.2002516.qx3zqy7
1 def celsius_to_kelvin(value_celsius):
value_kelvin = 0.0
2
1 test
passed
3
value_kelvin = value_celsius + 273.15
return value_kelvin
4
5
6
All tests
7' Your solution goes here '''
passed
8
9 value_c = 10.0
10 print (value_c, 'C is', celsius_to_kelvin(value_c), 'K')
11
12 value_k = float (input(O)
13 print(value_k, 'K is', kelvin_to_celsius (value_k), 'C')
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