The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is:

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is:

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter12: Exception Handling

Section: Chapter Questions

Problem 8RQ

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The given program reads a list of single-word first names and ages (ending with-1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 Here is the code that needs to be corrected: # Split input into 2 parts: name and age#parts = input().split()#name = parts[0]#while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.#age = int(parts[1]) + 1# print('{} {}'.format(name, age))# Split input into 2 parts: name and ageparts = input().split()#namename = parts[0]#if user enters -1while name != '-1':#try blocktry:age = int(parts[1]) + 1#exceptionexcept Exception as ex:#set age equal to 0age = 0# Get next…
s and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 419894.2696446.qx3zqy7 #include <string>#include <iostream> using namespace std; int main() { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl; cin >> inputName; } return 0;}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 main.cpp #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) {string inputName;int age;// Set exception mask for cin streamcin.exceptions(ios::failbit); cin >> inputName;while(inputName != "-1") {// FIXME: The following line will throw an ios_base::failure.// Insert a try/catch statement to catch the exception.// Clear cin's failbit to put cin in a useable state.cin >> age;cout << inputName << " " << (age + 1) << endl; cin >> inputName;}return 0;}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 √
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18Lua 21Mary Beth 19Stu 33-1 then the output is: Lee 19Lua 22Mary 0Stu 34 #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl;…
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Java programming See attached The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 NameAgeChecker.java import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker {public static void main(String[] args) {Scanner scnr = new Scanner(System.in); String inputName;int age;inputName = scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatchException.// Insert a try/catch statement to catch the exception.age = scnr.nextInt();System.out.println(inputName + " " + (age + 1));inputName = scnr.next();}}}
Challenge 2: InvalidNumbers.java Write a program InvalidNumbers that asks the user to enter a positive integer. The program will warn the user if a valid integer is not entered using the InputMismatchException and ask to enter again. The program should also throw an exception if the user enters negative numbers. Write the program and test it using negative numbers, doubles, and very large numbers.