The following member function for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. NumberList::printList( ) {ListNode *p = head; while(p){cout << p->value; p++;} }
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The following member function for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it.
NumberList::printList( )
{
ListNode *p = head; while(p)
{
cout << p->value; p++;
}
}
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- The following member function for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. NumberList::printList( ) {ListNode *p = head; while (p->next) { cout << p->value; p = p->next;} }The following member function for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. NumberList::printList( ) {while(head) { cout << head->value; head = head->next;} }Every time you write a non-const member function for a linked list, you should always think about if that function is preserving your class invariants. Group of answer choices A. True B. False
- struct insert_at_back_of_dll { // Function takes a constant Book as a parameter, inserts that book at the // back of a doubly linked list, and returns nothing. void operator()(const Book& book) { / // TO-DO (2) |||| // Write the lines of code to insert "book" at the back of "my_dll". // // // END-TO-DO (2) ||| } std::list& my_dll; };struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };Multiple choice in data structures void doo(node<int>*root){ if(root !=0) { node<int>*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do? a. swap the first item with the last item in the linked list b. set the first item in the linked list as the last item c. doesn't do anything because the root parameter is passed by value d. change the root item in the binary tree with the farthest leaf item
- C++ ProgrammingActivity: Queue Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. #include "queue.h" #include "linkedlist.h" class SLLQueue : public Queue { LinkedList* list; public: SLLQueue() { list = new LinkedList(); } void enqueue(int e) { list->addTail(e); return; } int dequeue() { int elem; elem = list->removeHead(); return elem; } int first() { int elem; elem = list->get(1); return elem;; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } int collect(int max) { int sum = 0; while(first() != 0) { if(sum + first() <= max) { sum += first(); dequeue(); } else {…struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };Duplicate Set This function will receive a list of elements with duplicate elements. It should add all of the duplicate elements to a set and return the set containing the duplicate elements. A duplicate element is an element found more than one time in the specified list. The order of the set does not matter. Signature: public static HashSet<Object> duplicateSet(ArrayList<Object> list) Example: INPUT: [2, 4, 5, 3, 3, 5] OUTPUT: {5, 3}
- In C++ Plz LAB: Grocery shopping list (linked list: inserting at the end of a list) Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts ItemNode.h Default Code: #include <iostream>#include <string>using namespace std; class ItemNode {private: string item; ItemNode* nextNodeRef; public: // Constructor ItemNode() { item = ""; nextNodeRef = NULL; } // Constructor ItemNode(string itemInit) { this->item = itemInit; this->nextNodeRef = NULL; } // ConstructorItemNode(string itemInit, ItemNode *nextLoc) {this->item = itemInit;this->nextNodeRef = nextLoc;} // Insert node after this…C++ ProgrammingActivity: Queue Linked List Explain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. SEE ATTACHED PHOTO FOR THE PROBLEM #include "queue.h" #include "linkedlist.h" class SLLQueue : public Queue { LinkedList* list; public: SLLQueue() { list = new LinkedList(); } void enqueue(int e) { list->addTail(e); return; } int dequeue() { int elem; elem = list->removeHead(); return elem; } int first() { int elem; elem = list->get(1); return elem;; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } int collect(int max) { int sum = 0; while(first() != 0) { if(sum + first() <= max) { sum += first();…Problem Description: Q1) Write a method public static void downsize (LinkedList employeeNames, int n) that removes every nth employee from a linked list. Q2) Write a method public static void reverse (LinkedList strings) that reverses the entries in a linked list.