Q2/ 7 A steel bolt 0.005 m² in cross-section is subjected to a Static mean load of 200 KN. What Value of Completely reversed direct fatigue load will Produce failure in 10² Cycles? Use the GERBER relationsip and assume that the yield sureg. Strength of the steel is 400 MN/m² and the Stress required to Produce failure at lot Cycles under zero. Mean Stress Condition is 300 MN/m².
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- A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The wire is made of a copper alloy having a stress-strain relationship that may be described mathematically by =18,0001+30000.03(=ksi) in which is nondimensional and has units of kips per square inch (ksi). (a) Construct a stress-strain diagram for the material. (bj Determine the elongation, of the wire due to the Forces P. (c) IF the forces are removed, what is the permanent set of the bar? (d) If the forces are applied again, what is the proportional limit?Solve the preceding problem if the diameter is 480 mm, the pressure is 20 MPa, the yield stress in tension is 975 MPa, the yield stress in shear is 460 MPa, the factor of safety is 2,75, the modulus of elasticity is 210 GPa, Poissorfs ratio is 0.28, and the normal strain must not exceed 1190 x 10" . For part (b), assume that the tank thickness is 8 mm and the measured normal strain is 990 x 10~A steel plate is subjected to a constant amplitude uniaxial fatigue loads to produce stresses, max = 180 MPa and min = -40 MPa. The static properties of the steel are YS= 500 MPa, UTS= 600 MPa, E= 207 GPa and Kc= 100 MPa-m1/2 . If the plate contains an initial through the thickness edge crack of 0.5 mm how many fatigue cycles will be required to break the plate. Please state any assumptions you make.
- Find the equivalent stresses at Points 1 and 2 of the element with given geometry and loading conditions according to the Maximum shear stress hypothesis and the Maximum strain energy hypothesis. Shaft diameter: 20 mm, Shaft Length 120 mm, F1 = 750N, F2 = 3000N, Mb = 2400 N.mm. Steel if St37 and Safety coefficient is 2 If taken, will this stick work safely under these operating conditions? (Yield of given steel Strength 225 Mpa, Tensile strength 370 Mpa)A cylindrical steel bar 8 mm in diameter is loaded 1000 cycles per day with a load of 15560 N. How long until fatigue failure takes place? Note: stress force/area 500 450 400 350 Steel Allby 300 250 200 150 Brass Alloy 100 50 1.00E-07 Cycles to Failure, N 1.00E+04 1.00E+05 1.00E-06 1.00E+08 100E+09 1.00E+10 , The bar should not fatigue. ) The bar will fail in one cycle. ) 100 days ) 1000 days Stress Amplitude, MPaou A bar of steel has the minimum properties S,- 276 MPa, S,-413 MPa, and Su= 551 MPa. The bar is subjected to a steady torsional stress (r m) of 103 MPa and an alternating bending stress (oa ) of 172 MPa. Find the factor of safety guarding against a static failure, and either the factor of safety guarding against a fatigue failure or the expected life of the part. For the fatigue analysis use: (a) Modified Goodman criterion. (b) Gerber criterion. (c) ASME-elliptic criterion note // assume the Kr and Ks equal 1
- Carbon Steel L=100mm dsmall= 20mm moment of inertia ratio between stepped cross-sectional area = 1:2 F=2500 N at A and a fillet radius at the step of 2mm -loading cycles that the design can withstand before fatigue failure - calculate cycles using goodman line and max stress from static analysis. -determine the effect of the 2mm fillet ratio on the fatigue analyisis. constant force at A8. Refer to the figure below. Even though the cyclic loading accidentally caused the stresses to exceed the levels at point A slightly (as marked by the red arrow), the machine part may not break instantly according to the Modified Goodman fatigue failure criterion. True_ or False Alternating stress a Yield (Langer) line Soderberg line I A m Gerber line Midrange stress om Load line, slope r = Modified Goodman line Sy ASME-elliptic line Sut SalSmpls find box ur answer Determine the value of the von Mises stress at point A. The von Mises stress at point A is This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold- drawn steel and is loaded by the forces F= 0.55 kN, P = 4 kN, and T = 25 N-m. Given: Sy= 280 MPa. 5 15-mm D. 100 mm- MPa.
- In the picture there is a sketch of a socket wrench. Assume the wrench is held at a fixed point “A”. The yield stress of the material is known to be 400 MPa. Answer the questions below Describe the stresses at point “A” and their causes and calculate the stresses. Determine the factor of safety against yield assuming the Tresca yield criteria. Determine the factor of safety against yield assuming the von Mises yield criteria using both principal stresses and “Cartesian” stresses. Do your values match or not, and is this expected? Explain. Do the calculated values make sense with the respect to the Tresca value? Explain, why or why not?A bar of steel has the minimum properties Se = 276 MPa, Sy = 413 MPa, and Sut = 551 MPa. The bar is subjected to a steady torsional stress of 103 MPa and an alternating bending stress of 172 MPa. Find the factor of safety guarding against a static failure, and either the factor of safety guarding against a fatigue failure or the expected life of the part. For the fatigue analysis use: (a) Modified Goodman criterion. (b) Gerber criterion. (c) ASME-elliptic criterion.The cold-drawn AISI 1040 Q&T at 205 ◦C steel bar shown in the figure is subjected to a completely reversed axial load fluctuating between 28 kN in compression to 28 kN in tension. Estimate the fatigue factor of safety based on achieving infinite life, and the yielding factor of safety for the following cases. If infinite life is not predicted, estimate the number of cycles to failure.a) for the part given in Fig 2(a) and b) for the part given in Fig. 2 (b) using the same dimensions (W=25mm, r=3mm, the thickness of 10 mm)