I need help with both the charts please Date:Name:(0-e)Chi Square - Simple ProblemsX² =Σx* critical valuesprobability.102.706 3.841df.90.50.05.025.995.000 .016.2111.4555.024.0101.386 4.605 5.9917.3783.072.5842.366 6.251 7.815 9.3484..207 1.064 3.357 7.779 9.48811.1431. If two brown mice are bred together, 35 of their 100 offspring are white.You hypothesize that the parents are heterozygous (Bb x Bb), support your claimusing a chi square.ta (orh esuhObservedExpected(Observed - Expected)?ExpectedBrown MiceWhite MiceSummed X =ANALYSIS: .2. A litter of mice was found in the lab, but no one wrote down what their parents were. In this type of mouse, earscan be curled due to a recessive allele. In the unknown litter, 8 mice have curled ears and 6 mice have normal ears.You hypothesize that the parents were Bb x bb. Support your claim with a chi square analysis.ObservedExpected(Observed - Expected)?ExpectedCurled EarsNormal EarsSummed X =ANALYSIS:www.hiologvcorner.com

Name: Date: Chi Square - Simple Problems X² = %3D x* critical values probability df 90 50 .10 .05 .025 995 .000 .016 .010 .211 2.706 3.841 5.024 .455 1.386 4.605 5.991 7.378 2.366 6.251 7.815 9.348 1 072 584

Name: Date: Chi Square - Simple Problems X² = %3D x* critical values probability df 90 50 .10 .05 .025 995 .000 .016 .010 .211 2.706 3.841 5.024 .455 1.386 4.605 5.991 7.378 2.366 6.251 7.815 9.348 1 072 584

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter13: Artifacts And Noise In Medical Instrumentation

Section: Chapter Questions

Problem 7P

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Question

I need help with both the charts please

Date:
Name:
(0-e)
Chi Square - Simple Problems
X² =
Σ
x* critical values
probability
.10
2.706 3.841
df
.90
.50
.05
.025
.995
.000 .016
.211
1
.455
5.024
.010
1.386 4.605 5.991
7.378
3
.072
.584
2.366 6.251 7.815 9.348
4.
.207 1.064 3.357 7.779 9.488
11.143
1. If two brown mice are bred together, 35 of their 100 offspring are white.
You hypothesize that the parents are heterozygous (Bb x Bb), support your claim
using a chi square.
ta (or
h esuh
Observed
Expected
(Observed - Expected)?
Expected
Brown Mice
White Mice
Summed X =
ANALYSIS: .
2. A litter of mice was found in the lab, but no one wrote down what their parents were. In this type of mouse, ears
can be curled due to a recessive allele. In the unknown litter, 8 mice have curled ears and 6 mice have normal ears.
You hypothesize that the parents were Bb x bb. Support your claim with a chi square analysis.
Observed
Expected
(Observed - Expected)?
Expected
Curled Ears
Normal Ears
Summed X =
ANALYSIS:
www.hiologvcorner.com

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Chi square test is goodness of fit test.

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