n=430 and ˆpp^ (p-hat) =0.88, find the margin of error at a 90% confidence level Give your answer to three decimals
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If n=430 and ˆpp^ (p-hat) =0.88, find the margin of error at a 90% confidence level
Give your answer to three decimals
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- If n=110 and ˆpp^ (p-hat) =0.71, find the margin of error at a 90% confidence levelGive your answer to three decimals.The odds difference = exp((0.15*20)-(0.15*30)), the standard error(se) = 0.06 which is on the scale of the linear predictor and not the odds. How to find the CI of the odds difference? Using simply the odds difference +- 1.96*se is incorrect. Pls explain alsoCalculate b0 value and Mean Absolute Error!