Mendelian Genetics - More Practice AAA Ha b Bb bb 1. A tetrahybrid individual, AaBbCcDd, is crossed with AABbCcdd: AaBbCcDd x AABbCcdd Use the multiplication and addition rules from lecture to calculate the probabilities that their offspring will have the following genotypes (assume independent assortment): 0.5 0.25 0.25 0.5 A. AABBCCdd 2/21 2/4 1/2 1/4 3/4 = 0.015825 1/64 ソム B. AabbCcdd podated 4/2024 C

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
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Chapter14: Human Inheritance
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Mendelian Genetics - More Practice
AAA Ha
b Bb bb
1. A tetrahybrid individual, AaBbCcDd, is crossed with AABbCcdd: AaBbCcDd x AABbCcdd
Use the multiplication and addition rules from lecture to calculate the probabilities that their
offspring will have the following genotypes (assume independent assortment):
0.5 0.25 0.25 0.5
A. AABBCCdd
2/21
2/4 1/2 1/4 3/4 = 0.015825 1/64
ソム
B. AabbCcdd
podated 4/2024
C
Transcribed Image Text:Mendelian Genetics - More Practice AAA Ha b Bb bb 1. A tetrahybrid individual, AaBbCcDd, is crossed with AABbCcdd: AaBbCcDd x AABbCcdd Use the multiplication and addition rules from lecture to calculate the probabilities that their offspring will have the following genotypes (assume independent assortment): 0.5 0.25 0.25 0.5 A. AABBCCdd 2/21 2/4 1/2 1/4 3/4 = 0.015825 1/64 ソム B. AabbCcdd podated 4/2024 C
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