I WILL RATE HIHG IF YOU ANSWER ALL POINTS PLEASE *13 1. The solution to Part 1 should have looked like this.(a)a =Consider the sketch below. Adjust the colored sliders so that the correspondingvo, v, and a vectors are oriented in the correct directions.t =Top of cliffSYo✔m/s✔m/s²YVOaBottom of cliffYIt takes 2.96 s for a rock to hit the ground when it is thrown straight up from a cliff with an initialvelocity of 7.00 m/s. Assume all values are correct upto 3 significant figures.VoVUsing the notation Ay=y-y for displacement, y for position after time t, yo for the initialposition, v for velocity after time t, vo for initial velocity, and a for acceleration, determinewhat quantities are known and what are unknown.• Enter the values of some known quantities below.• Make sure you account for the signs of the vectors using the coordinate system used inPart 1.Enter to 3 significant figuresVo=xa Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and2. the rock's journey down? Is it possible to solve without splitting the motion into two parts?Ay = vt(vo + v)2v=v₁ + at²= √²+2aAyAy=v₁t+1=1/1at²Ay=Ду- t(c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value.Enter to 3 significant figuresh=✔m(d) How long would it take the rock to reach the ground if it is thrown straight down with the samespeed instead of up?Enter to 3 significant figurest =✔SSense-making: Check if the answer in part (d) is less than the time in part (a).

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Science

Physics

I WILL RATE HIHG IF YOU ANSWER ALL POINTS PLEASE *13

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 53P: A surveyor measures the distance across a straight river by the following method: starting directly...

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Question

I WILL RATE HIHG IF YOU ANSWER ALL POINTS PLEASE *13

1. The solution to Part 1 should have looked like this.
(a)
a =
Consider the sketch below. Adjust the colored sliders so that the corresponding
vo, v, and a vectors are oriented in the correct directions.
t =
Top of cliff
S
Yo
✔m/s
✔m/s²
Y
VO
a
Bottom of cliff
Y
It takes 2.96 s for a rock to hit the ground when it is thrown straight up from a cliff with an initial
velocity of 7.00 m/s. Assume all values are correct upto 3 significant figures.
Vo
V
Using the notation Ay=y-y for displacement, y for position after time t, yo for the initial
position, v for velocity after time t, vo for initial velocity, and a for acceleration, determine
what quantities are known and what are unknown.
• Enter the values of some known quantities below.
• Make sure you account for the signs of the vectors using the coordinate system used in
Part 1.
Enter to 3 significant figures
Vo=
x
a

Something to think about: Do you need to split the trip into two parts: 1. the rock's journey up, and
2. the rock's journey down? Is it possible to solve without splitting the motion into two parts?
Ay = vt
(vo + v)
2
v=v₁ + at
²= √²+2aAy
Ay=v₁t+1=1/1at²
Ay=
Ду
- t
(c) Calculate the height of the cliff. Note: The height of the cliff should be a positive value.
Enter to 3 significant figures
h=
✔m
(d) How long would it take the rock to reach the ground if it is thrown straight down with the same
speed instead of up?
Enter to 3 significant figures
t =
✔S
Sense-making: Check if the answer in part (d) is less than the time in part (a).

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