Dot Product Learning Goal: To use the dot product to find the components of forces acting in arbitrary directions. A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C = (-4.04, 0, 0) and connected to the ceiling at point A-(-4.92,3.79, 4.87). The three legs connect at point D-(0, 3.23, 2.00), where two forces, F and P, act. Force F is given by F-9.601-13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a-120.0.3-49.0°, and y-55.6 for the x, y, and z axes, respectively. Part C -Determining the force along a member Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8k N. Express your answer to three significant figures and include the appropriate units. You did not open hints for this part. ANSWER: FDA- Part D - Finding the component of a force perpendicular to a direction Given F-9.00 -13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the perpendicular and parallel components of F (F-F+F) with respect to DA equals F. Express your answer in component form. Express your answers, separated by commas, to three significant figures. You did not open hints for this part. ANSWER: F DA iN,j N, KN Dot Product Learning Goal: To use the dot product to find the components of forces acting in arbitrary directions. A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C=(-4.04, 0, 0) and connected to the ceiling at point A=(-4.92, 3.79, 4.87). The three legs connect at point D = (0, 3.23, 2.00), where two forces, F and P, act. Force F is given by F-9.60 i 13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a 120.0.3-49.0°. and y-55.6 for the x, y, and z axes, respectively. Part C - Determining the force along a member Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8 k N. Express your answer to three significant figures and include the appropriate units. You did not open hints for this part. ANSWER: FDA- Part D - Finding the component of a force perpendicular to a direction Given F 9.60 i 13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the perpendicular and parallel components of F (F F +F) with respect to DA equals F. Express your answer in component form. Express your answers, separated by commas, to three significant figures. You did not open hints for this part. ANSWER: F DA= i N,j N, k N

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Dot Product
Learning Goal:
To use the dot product to find the components of forces acting in arbitrary directions.
A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C = (-4.04, 0, 0) and connected to the ceiling at point
A-(-4.92,3.79, 4.87). The three legs connect at point D-(0, 3.23, 2.00), where two forces, F and P, act. Force F is given by
F-9.601-13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a-120.0.3-49.0°, and y-55.6 for the x, y, and z axes,
respectively.
Part C -Determining the force along a member
Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8k N.
Express your answer to three significant figures and include the appropriate units.
You did not open hints for this part.
ANSWER:
FDA-
Part D - Finding the component of a force perpendicular to a direction
Given F-9.00 -13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the
perpendicular and parallel components of F (F-F+F) with respect to DA equals F. Express your answer in component form.
Express your answers, separated by commas, to three significant figures.
You did not open hints for this part.
ANSWER:
F DA
iN,j N, KN
Transcribed Image Text:Dot Product Learning Goal: To use the dot product to find the components of forces acting in arbitrary directions. A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C = (-4.04, 0, 0) and connected to the ceiling at point A-(-4.92,3.79, 4.87). The three legs connect at point D-(0, 3.23, 2.00), where two forces, F and P, act. Force F is given by F-9.601-13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a-120.0.3-49.0°, and y-55.6 for the x, y, and z axes, respectively. Part C -Determining the force along a member Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8k N. Express your answer to three significant figures and include the appropriate units. You did not open hints for this part. ANSWER: FDA- Part D - Finding the component of a force perpendicular to a direction Given F-9.00 -13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the perpendicular and parallel components of F (F-F+F) with respect to DA equals F. Express your answer in component form. Express your answers, separated by commas, to three significant figures. You did not open hints for this part. ANSWER: F DA iN,j N, KN
Dot Product
Learning Goal:
To use the dot product to find the components of forces acting in arbitrary directions.
A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C=(-4.04, 0, 0) and connected to the ceiling at point
A=(-4.92, 3.79, 4.87). The three legs connect at point D = (0, 3.23, 2.00), where two forces, F and P, act. Force F is given by
F-9.60 i 13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a 120.0.3-49.0°. and y-55.6 for the x, y, and z axes,
respectively.
Part C - Determining the force along a member
Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8 k N.
Express your answer to three significant figures and include the appropriate units.
You did not open hints for this part.
ANSWER:
FDA-
Part D - Finding the component of a force perpendicular to a direction
Given F 9.60 i 13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the
perpendicular and parallel components of F (F F +F) with respect to DA equals F. Express your answer in component form.
Express your answers, separated by commas, to three significant figures.
You did not open hints for this part.
ANSWER:
F DA=
i N,j N, k N
Transcribed Image Text:Dot Product Learning Goal: To use the dot product to find the components of forces acting in arbitrary directions. A three-legged structure is shown below. It is attached to the ground at points B = (4.04,0,0) and C=(-4.04, 0, 0) and connected to the ceiling at point A=(-4.92, 3.79, 4.87). The three legs connect at point D = (0, 3.23, 2.00), where two forces, F and P, act. Force F is given by F-9.60 i 13.5j+24.8 k N:P has magnitude 50.0 N and direction angles a 120.0.3-49.0°. and y-55.6 for the x, y, and z axes, respectively. Part C - Determining the force along a member Determine the magnitude, FA, acting along member DA, due to the applied force F-9.60 i-13.5j+24.8 k N. Express your answer to three significant figures and include the appropriate units. You did not open hints for this part. ANSWER: FDA- Part D - Finding the component of a force perpendicular to a direction Given F 9.60 i 13.5j +24.8 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the perpendicular and parallel components of F (F F +F) with respect to DA equals F. Express your answer in component form. Express your answers, separated by commas, to three significant figures. You did not open hints for this part. ANSWER: F DA= i N,j N, k N
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