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- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 13% per year? Why is yours the correct choice? Alternative First Cost X $-45,000 Maintenance cost, per $-9000 Year Salvage Value $1,000 Life 5 years Y $-55,000 $-4000 $6,500 5 years The present worth of alternative X is $ 13888 and that of alternative Y is $ 44459.4 Alternative X is selected by the company.Emerson Electric manufactures compressors for air conditioners. It needs replacement equipment to improve one of its manufacturing lines. Select between two options using the MARR of 14% per year and a future worth analysis for the expected use period. What are the future values of each option? Option First cost, S A B -64,000-76,000 -16,000-22,000 AOC, $ per year Expected salvage value 8,000 11,000 Expected use, years 3 6Acme Molding is examining 5 alternatives for a piece of material handling equipment. Each has an expected life of 8 years with no salvage value, and Acme's MARR is 12%. Using an incremental analysis, which material handling alternative should be chosen? The table below includes initial investment, net annual income, and IRR for each alternative. Alternatives A В C D E Capital investment $12,000 $2,500 $12,500 $2,520 $14,400 $3,050 $16,250 $3,620 $20,000 $4,400 Net annual income IRR 12.99% 12.04% 13.48% 14.99% 14.61%
- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 10% per year? Why is yours the correct choice? Alternative First Cost Maintenance cost, per Year Salvage Value Life X $-25,000 $-8000 $1,000 5 years Y $-55,000 $-2000 $2,000 5 years and that of alternative Y is $1 The present worth of alternative X is $. Alternativ (Click to select) is selected by the company.Reference: Case Study S Dunn Manufacturing is considering the following two alternatives. The cost information for the two proposals for replacing an equipment are provided are in table below. Initial cost Benefits/year Machine X $120,000 $20,000 for the first 10 years and $9,000 for the next 10 years Life Salvage value $40,000 MARR 5.2. The NPW of machine X is A) $35,158 B) $48,192 C) $50,752 Machine Y $96,000 $12,000 per year for 20 years. 20 years 8% $20,000A firm is trying to decide which of two machines to purchase as described in in the table below. Using the interest rate 9% or 0.09, use present worth analysis to determine which machine, if either, should be purchased. Show all your work. Machine: A - B First Cost: $800 - $600 Annual Net Benefit: $130 - $230 Salvage Value: $40 - $20 Usefil Life (years): 9 - 3
- Question 3. Choose the best piping systems as shown in the table below using Annual Worth method (MARR: 6%). Concrete piping UPVC piping Initial cost (OR) Ca Initial cost (OR) Annual 0&M (OR/y)" 10000 Annual O&M (OR/yr) 5000 Rehabilitation cost at the 120000 5th year Useful life (years)¤ 10 Useful life (years)= 20 Ca 1720102 1136000 1828000:What is the decision criteria for Payback Period (PBP) method? A construction company is considering the purchase of a new piece of equipment. Relevant information concerning the equipment follows: Cost of the equipment $220,000 Annual cost savings from new equipment $44,000 Life of the new equipment 10 years Compute the payback period for the equipment. If the company requires a payback period of five years or less, would the equipment be purchased?The Fence Company is setting up a new production line to create top rails. The relevant data for two alternatives are shown below. Flow Line Manufacturing Cell Installed Cost Expected Life Salvage Value Variable Cost per Top Rail Click here to access the TVM Factor Table Calculator $15,000 5 years $0 $6.00 $10,000 5 years $0 $7.00
- A firm is considering three mutually exclusive alternatives as a part of an upgrade to an existing transportation network. If the MARR is 10% per year, which alternative(if any) should be chosen using the IRR analysis procedure? Use trial & error and show your calculations. A B C Initial Cost 40000 30000 20000 Annual Revenue 10400 8560 7750 Annual Cost 4000 3000 2500 Salvage Value 3000 2500 2000 Useful Life 20 20 10As an engineer, you have been asked to recommend a new cooling system for a large warehouse. You have narrowed it down to three different systems with the associated costs shown below If the minimum attractive rate of return in 10%, which system would you recommend. Cooling system A В C $250,000 $75,000 $300,000 $60,000 $36,000 $375,000 $80,000 $45,000 9 years Installation costs Annual operating costs Salvage value Lifespan None 5 years 7 yearsA company is considering two alternatives with regards to equipment which it needs. The alternatives are as follows: Alternative A: Purchase Cost of Equipment 703,668700,000 Salvage Value 100,454100,000 Daily operating cost 501500 Economic life, years 10 Alternative B: Rental at 1,5751,500 per day. At 18% interest, how many days per year must the equipment be in use if Alternative A is to be chosen.