152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V
152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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Question
Transcribed Image Text:152-240° V
C
a
n
1520° V
ial
-8+j8 N
Vab
in
152-120° V
Vca
b
ibl
1
Vbc
icl
-8+j80-8+j8 N
Find the line currents and line-to-line voltages.
(Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2
digits)
ial
ibl
ici
=
=
=
0
A
° A
L
° A
Vab
Ubc
=1
=
Vca =
° V
V
° V
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