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10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V

10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V
Transcribed Image Text:10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V
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