Minitab Project 1

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Southern New Hampshire University *

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Statistics

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Jan 9, 2024

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Jonathan Dam 02/26/16 Mrs. Karen Wells Statistics I Minitab Project #1b a. The minimum is 110, the first quartile is 234.25, the median is 247.5, the third quartile is 255, and the maximum is 273. b. IQR=Q3-Q1=255-234.25=20.75 The interquartile range is the middle 50% of one’s data.

c. Lower Outlier Boundary=Q1-(1.5*IQR)=234.25-(1.5*20.75)=203.125 Upper Outlier Boundary=Q3+(1.5*IQR)=255+(1.5*20.75)=286.125 There is an outlier, it is the minimum, which is 110. It is an outlier because it falls beneath the lower outlier boundary. d. Range=maximum-minimum=273-110=163 Midrange=(maximum+minimum)/2=(273+110)/2=191.5 #2 a. Mean=33.14 Median=31.50 Mode(s)=26,27,28,32 Standard Deviation=9 Q1=27 Q3=37.25 Minimum=22 Maximum=63 b. IQR=Q3-Q1=37.25-27=10.25 Lower Outlier Boundary=Q1-(1.5*IQR)=27-(1.5*10.25)=11.625 Upper Outlier Boundary=Q3+(1.5*IQR)=37.25+(1.5*10.25)=52.625 There is an outlier. It is the maximum, which is 63. It is an outlier because it is higher than the upper outlier boundary. c. Trick question or typo? Midquartile a.k.a Median=31.50 or Midquartile Range=(Q3-Q1)/2=(37.25-27)/2=5.125 Range=maximum-minimum=63-22=41 #3

a. It is skewed to the right. b. The mean is larger than the median because this histogram is skewed to the right. c. Although the officer in question will thankfully not have to catch as many speeders as there are people who are following the rules of the road, yes the officer should watch over this road, for the majority of people who do follow the rules, their safety could potentially be better ensured with the presence of a law abiding official. d. Q1=23 Q3=33 Minimum=16 Maximum=52 IQR=10 e. Lower Outlier Boundary=Q1-(1.5*IQR)=23-(1.5*10)=8 Upper Outlier Boundary=Q3+(1.5*IQR)=33+(1.5*10)=48 There is an outlier. It is the maximum, which is 52. It is an outlier because it is higher than the upper outlier boundary. #4 a. Mean=16.36 Standard Deviation=14.52

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