You would like to send a 2100-byte chunk of data uslng TCP from Computer A to Computer B. TCPsegments are carrled In IP datagrams with a 20-byte header. IP datagrams are carrled In a data link framewith a 10-byte header. The maxlmum segment slze for TCP Is 800 bytes. The physlcal layer protocol cansupport a data rate of 1 Mbps. Assume a total round-trip time of 10 ms between the sender and therecelver.How many frames will need to be sent from Computer A to Computer B? What Is the size of eachTCP segment? Show your work

Answered: You would like to send a 2100-byte…

Principles of Information Security (MindTap Course List)

6th Edition

ISBN:9781337102063

Author:Michael E. Whitman, Herbert J. Mattord

Publisher:Michael E. Whitman, Herbert J. Mattord

Chapter6: Security Technology: Access Controls, Firewalls, And Vpns

Section: Chapter Questions

Problem 2RQ

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In a bit-oriented link-layer protocol, the start and end of a frame are each marked by a flag, which is a sequence of exactly 6 consecutive 1 bits. Bit stuffing is used during the rest of the frame: after sending 5 consecutive 1 bits, a 0 is added. The bits below contain an example frame, with the leftmost bit received first. The content of the frame is a sequence of bytes, sent most significant bit first. Put the values of the first four bytes of the frame content, in order, in the four answer boxes below. You may enter the values in either decimal (e.g. 76, 123) or hexadecimal (e.g. 2a, f7). 00101011111010001111110011100111110000111101111101010110100010010011111101101100100 57−240−123−229
Suppose an extension of TCP allows window size much larger than 64 KB. Assume the extended TCP runs over a 100-Mbps link with RTT 100 ms, segment size is 1 KB, and receiving window size is 1 MB. How long does it take to send a 200 KB file?
The maximum transmission unit on an Ethernet link is 4500 bytes. This means that the IP packets sent over Ethernet cannot be larger than 4500 bytes including the IP header. Suppose the application layer sends a 6500-byte message. The transport layer uses TCP with no options. The network layer is using IP version 4. Obviously, the IP layer will have to fragment the data. Provide the length of new datagrams (after fragmentation). Provide the Flag and offset of each of the new datagrams.
P27. Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A. In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number? If the first segment arrives before the second segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number, the source port number, and the destination port number? If the second segment arrives before the first segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number? Suppose the two segments sent by A arrive in order at B.…
Consider a TCP connection betweek two hosts between A and B. The first data byte sent by A is numbered 1. The LastByteRcvd at B is 500. Then, the range of values SendBase at A may take is from to 500
Host A sends the information of size 3000 bytes to Host B using TCP protocol. As long as Host B receives each packet in size 1000 bytes, Host B must acknowledge Host A. We assume the header size in each packet is 40 bytes, the starting sequence number used by Host A is 1000, and the window size of the sender side is 3000 bytes. What is the value of RCV.NXT in Host B when the second packet in Host A is sent out and acknowledged? Question options: 1000 2000 3000 4000
You need to send a 2100-byte chunk of data using TCP from Computer A to Computer B. TCP segments are carried in IP datagrams with a 20-byte header. IP datagrams are carried in a data link frame with a 10-byte header. The maximum segment size for TCP is 800 bytes. The physical layer protocol can support a data rate of 1 Mbps. The round-trip time is10 ms between the sender and the receiver. Data must be sent over three links: (1) from Computer A to the first router, (2) from the first router to the second router, and (3) from the second router to Computer B. How long will it take to create a TCP connection, deliver the data from Computer A to Computer B, and close the connection? Ignore any effects of TCP congestion control or flow control. All links are lightly loaded so there are no queuing delays. Show your work.
3. Consider a simple application-level protocol built on top of UDP that allows a client to retrieve a file from a remote server residing at a well-known address. The client first sends a request with a file name, and the server responds with a sequence of data packets containing different parts of the requested file. To ensure reliability and sequenced delivery, client and server use a stop-and-wait protocol. Ignoring the obvious performance issue, do you see a problem with this protocol? Think carefully about the possibility of processing crashing. State conclusion: Provide Proof: Solution:
Consider a client connecting to a web server via a router as shown in Fig.Q2. Client A sends a request to the server to retrieve a 7.5 Mbytes file. Given that the segment size is 50 Kbytes, the round trip time (RTT) between the server and client is 10 ms, the initial slow-start threshold is 16 and the client's buffer always has a storage space of 1 Mbytes. Assume that TCP Reno is used, there is no loss during transmission and the headers of protocols are ignored. 400 Mbps 200 Mbps 400 Mbps Link a Link b Link c Client Web Server Fig.Q2 (a) Describe how the value of sending window changes as a function of time (in units of RTT) during the whole connection time. 2.
The filed “window size” in TCP header is in length of 16 bit. It allows 64KB as the maximal size for a TCP segment by default. Under some circumstances, the sending rate is pretty high and it results in a very short sending time (<2ms). But the end to end transmission delay is 50ms. Therefore the idle rate of a channel will be more than ⅔. How does TCP solve this problem?
Consider two hosts P and Q connected through a router R. The maximum transfer unit (MTU) value of the link between Pand Ris 1500 bytes, and between Rand Qis 820 bytes. A TCP segment of size 1400 bytes was transferred from P to Q through R, with IP identification value as 0x1234. Assume that the IP header size is 20 bytes. Further, the packet is allowed to be fragmented, i.e., Don't Fragment (DF) flag in the IP header is not set by P, Which of the following statements is/are correct? (a) Two fragments are created at R and the IP datagram size carrying the second fragment is 620 bytes. (b) If the second fragment is lost, P is required to resend the whole TCP segment. (c) TCP destination port can be determined by analysing only the second fragment. (d) If the second fragment is lost, R will resend the fragment with the IP identification value 0x1234
CIS269 Packet Translation Lab Break down the following IP datagram into its individual fields, listing the value of each. Hint: It’s an IP datagram containing a TCP segment containing another protocol… 45 00 00 31 94 00 40 00 80 06 1B 9F 80 A3 C9 29 D8 45 29 15 04 09 00 15 00 00 C3 A1 DF 65 A8 45 50 18 20 AA 8E 8C 00 00 43 57 44 20 66 75 6E 0D 0A

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