Vcc = 12 V 5k2 C2 -40kΩ Vout1 C1 2kQ H Vce = 5.8 V 1ko Vout2 10kQ 1kQ Vin 5mV

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Given:
Hie = 2.2 KΩ
Vcc = 12 V
VBE = 0.7 V

Solve for :
1. Ac circuit
2. β
3. Rin
4. Rin’
5. R01
6. Ro2
7. Ro’1
8. Ro’2
9. Av1
10. Av2
11. Vb/Vs
12. Avs1
13. Avs2
14. vo1
15. Vo2
16. Ai1
17. Ai2
18. Ib/Is
19. I0/Ic
20. Ais1
21. Ais2

 

Vcc = 12 V
5k2
C2
-40kΩ
Vout1
C1
2kQ
H
Vce = 5.8 V
1ko
Vout2
10kQ
1kQ
Vin
5mV
Transcribed Image Text:Vcc = 12 V 5k2 C2 -40kΩ Vout1 C1 2kQ H Vce = 5.8 V 1ko Vout2 10kQ 1kQ Vin 5mV
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