The tee section shown below is to carry a bending moment of 8440 N·m. It is to be mad plates welded together. If the load on the beam is a static load, would SAE 1020 hot-rolle be satisfactory for the plates? -175 mm 25 mm
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- Topic: COMBINED STRESS-AXIAL TENSION AND FLEXURE BENDING: STEEL DESIGN Please solve your Solution in a handwritten Note: It should be handwritten pleaseeee Questions A Tension member with no holes is subjected to axial loads of PD=68kN & PL=64kN.It is also subjected with bending moments of MDy=40kN-m & MLy=55kN-m. Is themember adequate? Steel is of A992 Gr 50 Specs. Use LRFD. Neglect the weight of the beam. Section properties:Lp = 1.863 md=459.99mmtw=9.02mmzx= 1835x10^3 mm^4Lr = 5.305 mLb = 4.8 mbf=191.26mmtf=16mmSx=1611x10^3 mm^4 Sy=195x10^3 mm^4Zy=303x 10^3 mm^4 Cb=1.32A bronze bar is fastened between a steel bar and an aluminum bar as shown in the figure. Axial loads are applied at the positions indicated. The allowable overall deformation is not to exceed 1.2 mm. Assume that the 2P Aluminum L- 1.5 m A= 550 mm E= 70 GPa Steel Bronze L= 2.0 m L= 1.0 m A= 600 mm A= 650 mm E= 200 GPa E= 83 GPa assembly is suitably braced to prevent buckling. Find the maximum permissible value of P.Specify a suitable aluminum casting alloy for a bar with square crosssection. Length of one side of the cross-section is 50 mm. The bar is subjected toan impact loading with a tensile force of 60 kN
- The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P = 20 KN is applied. %3D Steel E200 GPa A-600mm L1 m 2.0 m 0.6 m 1.5 m Pa20 KN Aluminum E-70 GPa A=900mm L-1.5 m What is the ratio of the deformation of steel to deformation of aluminum?1. If the allowable stress of a revolving steel is 150 MPa, what is the equivalent angular velocity which will produce such stress. The mean diameter is 440mm. 2. See connection figure below. The rivets is 7/8 in. in diameter. According to the rivert supplier, the allowable stresses for the material are t = 15 ksi and Ob = 32 ksi. What is the allowable load of the connection? L4 x 3-1/2 W18 x 86 W24 x 117 Girder BeamA E E E E X 1 E E - E E E GD 1 I 2 3 4 I 5 Condition #1: A structural support for a machine is subjected to a static compression load of 20 kN. The support is manufactured from a circular rod made from SAE 1040 Hot Rolled steel. Specify suitable diameter for the cross section of the rod based on the basic size. Steel data are available in Table A-10 from the textbook. A-10 Typical properties of carbon and alloy steels. Ultimate strength, s Yield strength, s, Percent Material SAE no. Condition ksi MPa ksi MPa elongation 1020 Annealed 57 65 393 448 517 43 296 36 1020 Hot rolled 48 331 36 1020 Cold drawn 75 64 441 20 1040 Annealed 75 517 51 352 30 1040 Hot rolled 90 621 60 414 25 1040 Cold drawn WQT 700 WQT 900 WOT I 100 WOT 1300 97 669 82 565 16 1040 127 118 876 93 641 621 19 1040 814 90 22 1040 107 738 80 552 24 1040 87 600 63 434 32 1080 Annealed 89 614 54 372 25 1O80 OQT 700 OQT 900 OQT 1100 OQT L00 189 1303 972 141 129 12 1080 179 1234 889 13 1080 145 1000 103 710 17 1080 117 807 70…
- Calculate the shear yield stress (ksi) of A588 steel.← Expert Q&A Q6. A simply-supported beam spans 10 m and is made from a 700WB150 steel section. A static vertical concentrated load of 400 KN is applied as shown in Figure. In the event of a fire, the temperature of the steel rises at a constant rate of 15 °C per minute up to a maximum of 750 °C. Assume that, at 20 °C, the steel has a yield stress of 300 MPa and Young's Modulus of 200 GPa. The ambient temperature (before the fire starts) is 20 °C. Determine whether the beam will collapse during the fire, and if so, how long after the start of fire will this occur? 6 m Self weight 400 kN 4 mAn A36 steel plate with width of 400 mm and thickness of 12 mm is to beconnected to a plate of the same width and thickness by 34 mm diametersbolts, as shown in the figure (next slide). The holes are 2 mm larger thanthe bolt diameter. The yield strength of the steel plate is Fy = 248 MPa.Assume allowable tensile stress on net area is 0.60Fy. It is required todetermine the value of b such that the net width along bolts 1-2-3-4 isequal to the net width along bolts 1-2-4.a. Calculate the value of b in mm.b. Calculate the value of the net area for tension in plates in mm².c. Calculate the value of P so that the allowable tensile stress on net areawill not be exceeded.(Use at least 2 decimal points on your answers.)
- TENSION MEMBERS: THE SINGLE 200 X 10 mm STEEL PLATE IS CONNECTED TO A 12 mm THICK STEEL PLATE BY FOUR 16 mm DIAMETER RIVETS AS SHOWN IN THE FIGURE. THE RIVETS USED ARE A502 GRADE 2, HOT DRIVEN RIVETS. THE STEEL IS ASTM A36 WITH Fy = 248 MPa AND Fu = 400 MPa. DETERMINE THE VALUE OF P. a. P BASED ON TENSION OF GROSS AREA b. P BASED ON TENSION OF NET AREA c. P BASED ON BEARING OF PROJECTED AREA d. P BASED ON SHEAR RUPTURE (BLOCK SHEAR)The 10-mm-diameter steel bolt is surrounded by a bronze sleeve. The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. If the yield stress for the steel is (ay) MPa, and for the bronze (ay)or 520 MPa, determine the magnitude of the largest elastic load P 640 that can be applied to the assembly. E 200 GPa, Ebr= 100 GPa. 10 mm 20 mm Figure 2: Steel BoltDetermine the design tensile strength of the plate (200 × 100) mm connected to a 12 mm thick gussets, using 20 mm bolts shown below, if the yield and ultimate stress of the steel used are 250 MPa and 420 MPa respectively, fy= 250 MPa fu= 450 MPa