Answered: The pH of 300 mL solution made of 0.64…

The pH of 300 mL solution made of 0.64 M acetic acid and 1.06 M potassium acetate is (K₂ = 1.8 x 10-5) after the addition of 0.05 moles HCI Your Answer: Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter15: Acid-base Equilibria

Section: Chapter Questions

Problem 3ALQ: Mixing together solutions of acetic acid and sodium hydroxide can make a buffered solution. Explain....

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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The pH of 300 mL solution made of 0.64 M acetic acid and 1.06 M potassium
acetate is (K₂ = 1.8 x 10-5) after the addition of 0.05 moles HCI
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2. If an acetic acid/sodium acetate buffer solution is prepared from 100. mL of 0.10 M acetic acid what volume of 0.10 M sodium acetate must be added to have a pH of 4.00? 100. mL 50. mL 36 mL 18 mL
Mixing together solutions of acetic acid and sodium hydroxide can make a buffered solution. Explain. How does the amount of each solution added change the effectiveness of the buffer?
Amino acids are an important group of compounds. At low pH, both the carboxylic acid group (CO2H) and the amine group (NHR) are protonated. However, as the pH of the solution increases (say, by adding base), the carboxylic acid proton is removed, usually at a pH between 2 and 3. In a middle range of pHs, therefore, the amine group is protonated, but the carboxylic acid group has lost the proton. (This is called a zwitterion.) At more basic pH values, the amine proton is dissociated. What is the pH of a 0.20 M solution of alanine hydrochloride, [NH3CHCH3CO2H]Cl?
A friend asks the following: Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like NaOH is added, the HA reacts with the OH to form A. Thus the amount of acid (HA) is decreased, and the amount of base (A) is increased. Analogously, adding HCI to the buffered solution forms more of the acid (HA) by reacting with the base (A). Thus how can we claim that a buffered solution resists changes in the pH of the solution? How would you explain buffering to this friend?
8-55 We commonly refer to a buffer as consisting of approximately equal molar amounts of a weak acid and its conjugate base—for example, CH3COOH and CH3COO-. Is it also possible to have a buffer consisting of approximately equal molar amounts of a weak base and its conjugate acid? Explain.
A good buffer generally contains relatively equal concentrations of weak acid and conjugate base. If you wanted to buffer a solution at pH = 4.00 or pH = 10.00, how would you decide which weak acidconjugate base or weak baseconjugate acid pair to use? The second characteristic of a good buffer is good buffering capacity. What is the capacity of a buffer? How do the following buffers differ in capacity? How do they differ in pH? 0.01 M acetic acid/0.01 M sodium acetate 0.1 M acetic acid/0.1 M sodium acetate 1.0 M acetic acid/1.0 M sodium acetate
What mass of NH4Cl must be added to 0.750 L of a 0.100-M solution of NH3 to give a buffer solution with a pH of 9.26? (Him: Assume a negligible change in volume as the solid is added.)
How many grams of NaOH must be added to 1.00 L of a buffer made from 0.150 M NH3 and 10.0 g of NH4Cl so that the pH increases by one unit (e.g., from 5 to 6)? Ka for NH4+ is 5.61010.
The pH of 300 mL solution made of 0.96 M acetic acid and 0.86 M potassium acetate is (K₂ = 1.8 x 10-5) after the addition of 0.80 moles NaOH Your Answer: Answer
The pH of 300 mL solution made of 0.88 M acetic acid and 0.97 M potassium acetate is (Ka 1.8 x 10 5) after the addition of 0.07 moles HCI %3D Your Answer: Answer
please answer on 1-a,b,c,d. Clear handwriting or type in, thank you! 1. The mixture of anions is an effective blood buffer with the following acid-base equilibrium: HO" (aq) + HPO* (aq) H:POs (aq) + H;O (1) a. For the equilibrium above, what is the effect of decreasing the pH? (give shift) b. As a result of the shift, which ion H:PO, or HPO, would appear to increase? c. For the equilibrium above, what is the effect of increasing the pH? (give shift) d. As a result of the shifl, which ion H:PO, or HPO would appear to increase?
What is the pH of a buffer solution that is 0.214 M in ammonia and 0.390 M in ammonium chloride (NH4CI)? The Kü of ammonia is 1.8 x 10-5. (Two decimal places)