The center of mass of a system is at x = 2 m. There are three point masses in the system. The first mass (0.002 kg) is at x = 0.5 m. The second mass (0.006 kg) is at x = 1.2 m. Where is the third mass (0.004 kg) located? A. 2.47 m B. 4.11 m C. 3.18 m D. 3.95 m E. 1.69 m

The center of mass of a system is at x = 2 m. There are three point masses in the system. The first mass (0.002 kg) is at x = 0.5 m. The second mass (0.006 kg) is at x = 1.2 m. Where is the third mass (0.004 kg) located? A. 2.47 m B. 4.11 m C. 3.18 m D. 3.95 m E. 1.69 m

Name: Thanks 4.The center of mass of a system is at x = 2 m. There are three
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: Thanks 4.The center of mass of a system is at x = 2 m. There are three point masses in thesystem. The first mass (0.002 kg) is at x = 0.5 m. The second mass (0.006 kg) is at x =1.2 m. Where is the third mass (0.004 kg) located?A. 2.47 mB. 4.11 mC. 3.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Momentum And Collisions

Section: Chapter Questions

Problem 38P

See similar textbooks

Similar questions

The figure shows a distribution of several objects, in which m1 = 3.0 kg, m2 = 2.0 kg, and m3 = 1.0 kg a. What is the x-coordinate of thesystem’s center of mass?A. 1.67 mB. 1.83 mC. 2.5 mD. 2.75 mE. None of these b. What is the y-coordinate of thesystem’s center of mass?A. 1.5 mB. 1.83 mC. 2.17 mD. 2.75 mE. None of these
2. A 'small' asteroid with a mass of 800kg is moving through deep space with a constant velocity of 50 m/s. Suddenly the small asteroid collides with a large asteroid possessing a mass of 8,000kg. The large asteroid was initially at rest and the collision causes the small mass to become completely embedded within the larger one so that they are now one combined mass. a. What is the speed of the combined mass system after the collision? b. How many Joules of energy were lost due to the collision?
Object A approaches object B which is stationary. Velocity of object A is V = 28i + 5j - 3k in m/s. Mass of A = 10 kgs and that of B = 4 kgs. If the impact is perfectly inelastic, 1. Compute the x-component of the velocity after impact a. 28i b. 48i c. 32i d. 20i 2. Compute the z-component of the velocity after impact. a. 4.14k b. 2.14k c. 3.14k d. 5.14k
a. A binary system consists of star A with mass of 3.8 x 100 Kg and star B with mass of 3.2 x 1030 kg. Their centres are separated by 9.8 AU (1.5 x 10¹1m) Calculate how far the centre of mass of the system is from star A. b. What is the reduced mass of such system in part a? c. A point has coordinates (x,y,z) in cartesian coordinate system, use spherical coordinates as generalized coordinates to calculate dy d. Positions of two planets are given as (-4.00, 2.94,-0.10) AU and (6.41, 6.54,-0.37) AU. Find the distance between them? Attach File Browse Local Files Browse Content Collection
1. What is the momentum of a 2.3 kg ball going to 5.5 m/s 2. A bullet going 50 m/s has 120 kg m/s momentum. What is its mass? 3. What is the impulse imparted by a bullet that exerts 5 N for 2 seconds?
1. A 4.0kg block has a velocity of ( 2.0i – 4.0j) m/s.a. Find the x and y components of its momentum.b. Find the magnitude and direction of its momentum
The Moon is 60 Earth radii (i.e. 60 rEarth) from the center of the Earth and has a mass of 0.012 Earth masses (i.e. 0.012 mEarth) a. How many Earth radii is the center of mass (the “barycenter”) of the Earth-Moon system from the center of the Earth? b. Is the center of mass inside the Earth or outside the Earth? c. What point along the line from the center of the Earth to the center of the Moon orbits the barycenter of the Solar System in a (nearly) circular orbit (e.g. the center of the Earth, the barycenter of the Earth-Moon system, the midpoint, the center of the Moon)?
2. The 2 masses below are traveling in the same direction and experience an inelastic collision which has a final velocity of 47m/s. m 92kg a. What is the initial velocity of m, if the initial velocity of m, is 29.4m/s? b. What is the final momentum of m, + m2? C. What is the kinetic energy of m, before the collision?
1. A bullet moving at vo=1500[m/] hits a ballistic pendulum of mass M=2[kg] that hangs on a string of length 0.8[m]. The center of mass of the pendulum goes up a distance of 0.4 [m]. a. What is the angle 0 at that point? b. What is the mass m of the bullet? c. How much, in Joule, of the initial kinetic energy went into "Waste" (heat, sound, deformation).
8. A bullet having a mass of 0.05 kg moving with a velocity of 400 m/s penetrates a distance of 0.1 m into a wooden block firmly attached to the earth. Assume the accelerating force constant. Compute: a. The acceleration of the bullet b. The accelerating force. c. The time of acceleration d. The impulse of the collision
Center of Mass. c) The mass of the Sun is 2x1030 kg. The distance between the Earth and the Sun is 1.5x108 km. How does the distance between the CM of this system compare to the Sun’s radius of 700,000 km?
v) A very light rod (ignore its mass) of length L connects two particles of mass m and 2m. Find the location of the center of mass of the system relative to the position of mass 2m. a. ICM = 2L/3 b. xCM = L/3 C. XCM = = 3L/2 d. CCM = L/2