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Review Intelligent Tutoring Question 13.63 The oxidation of NO (released in small amounts in the exhaust of automobiles) produces the brownish-red gas NO, which is a component of urban air pollution. 2NO + 02 ZNO, The rate law for the reaction is rate - K(NOJ?(0,1. At 25°C, k = 7.1 x 10° L'mor?s. What would be the rate of the reaction if [NO] = 0.0010 mol L and (0,) - 0.034 mol L? rate = mol Ls! the tolerance is +/-2%

Review Intelligent Tutoring Question 13.63 The oxidation of NO (released in small amounts in the exhaust of automobiles) produces the brownish-red gas NO, which is a component of urban air pollution. 2NO + 02 ZNO, The rate law for the reaction is rate - K(NOJ?(0,1. At 25°C, k = 7.1 x 10° L'mor?s. What would be the rate of the reaction if [NO] = 0.0010 mol L and (0,) - 0.034 mol L? rate = mol Ls! the tolerance is +/-2%

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.35PAE: 11.35 For the reaction 2 NO(g) + 2 H?(g) — N,(g) + 2 H,O(g) at 1100°C, the following data have been...
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13.63

Review Intelligent Tutoring Question 13.63 The oxidation of NO (released in small amounts in the exhaust of automobiles) produces the brownish-red gas NO, which is a component of urban air pollution. 2NO + 02 ZNO, The rate law for the reaction is rate = K[NO)°(0,). At 25°C, k = 7.1 x 10° L?mor?s. What would be the rate of the reaction if (NO] = 0.0010 mol L and (0,) = 0.034 mol L? rate = mol Ls! the tolerance is +/-2%
Transcribed Image Text:Review Intelligent Tutoring Question 13.63 The oxidation of NO (released in small amounts in the exhaust of automobiles) produces the brownish-red gas NO, which is a component of urban air pollution. 2NO + 02 ZNO, The rate law for the reaction is rate = K[NO)°(0,). At 25°C, k = 7.1 x 10° L?mor?s. What would be the rate of the reaction if (NO] = 0.0010 mol L and (0,) = 0.034 mol L? rate = mol Ls! the tolerance is +/-2%
Expert Solution
Step 1

Given:

k=7.1×109 L2mol-2s-1[NO]=0.0010 mol L-1[O2]=0.034 mol L-1

Formula:

The given rate equation for the reaction is:

2NO+O2→2NO2

Rate=k[NO]2[O2]

Where,

k= rate constant

[NO]= Concentration of NO

[O2]= Concentration of O2

To find:

Rate

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