Required information In a refrigerator, 2.10 mol of an ideal monatomic gas is taken through the cycle shown in the figure. The temperature at point A is 698.0 K. P P2 1.30 kPa K What is the temperature at point D? D BI IC 1.50 m³ 2.25 m³ V
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week 5 #2
In a refrigerator, 2.10 mol of an ideal monatomic gas is taken through the cycle shown in the figure. The temperature at point A is 698.0 K. ( see picture )
What is the temperature at point D?
_____K
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- Five moles of a monatomic ideal gas in a cylinder at 27 is expanded isothermally from a volume of 5 L to 10 L. (a) What is the change in internal energy? (b) How much work was done on the gas in the process? (c) How much heat was transferred to the gas?The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If I mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule.The temperature of an ideal gas is raised from 298 K to 402 K in a process that increases the heat content of the gas by 1000 J. What is the = -R for the gas, and these are constant. Hint: It will be 2 work performed on the system by this process? Assume that c 'y helpful to evaluate AU for this process. 3 =-R and C R
- A system consisting of 0.0140 moles of a diatomic ideal gas is taken from state A to state Calong the path in the figure below. P (atm) 0.800 0.600 OC 0.400 0.200 V (L) 8 4 6 (a) How much work is done on the gas during this process? (b) What is the lowest temperature of the gas during this process? K Where does it occur? O Point A O Point B O Point C (c) Find the change in internal energy of the gas in going from A to C. Hint: Adapt the equation (for the change in internal energy of a monatomic ideal gas)AU = a diatomic ideal gas. (d) Find the energy delivered to the gas in going from A to C.The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule. Please solve with clarification of laws and with the order of units [Cal]Volech 28. A monatomic ideal gas initially at pressure Po = 10° Pa, volume Vo = 0.01 m³, and temperature To = 300 K is taken through the cycle shown in the figure. p %3D ЗР. a. Determine the change in internal energy from point A to point B. b. Determine the work done by the gas from point B to point C. Po c. Determine the heat released by the gas from point C to point D. d. Determine the net work done by the gas and the net heat absorbed by the gas. Vo 3V bhe s on the
- The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note Note that 1 literxatmosphere is equal to 101.325 joule. Sol": given Heat of melting ice at 1 atm pressure = 1.4363 kca kcal/ 2 = 1.4363 kcal/mole mole volume of ice = 0·0196 lts " water = 0.018 lts @ work done is define as w=pdv » w = P(V₁ hot W = 1 (0·018-00196) W = 0·0016 Cal Pay Kat Ans2 moles of ideal oxygen gas are kept at 273 K in a volume of 11.35 dm3 with a molar heat capacity at constant pressure, Cp of 29.4 J K–1 mol–1 (independent of temperature). If the gas is heated to 373 K at constant pressure in a reversible manner. a. What is the gas's final volume? b. How much work has been done on the gas system? c. How much heat does the system supplied ? d. What is the increase in gas's enthalpy? f. What is the increase in the internal energy of the gas? Kindly indicate the given. Thank youA process at constant pressure pressure takes n mole rigid diatomic from an initial temperature T to a final temperature 3T. Calculate the change in enthalpy, AH. Select one: O a. AU = 5n RT O b. Ο c. O d. AH = 9n RT ΔΗ = 11nRT AH = 7nRT
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