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- You are given opportunity to purchase product for $42, 000. The product will have annual operating expenses of $4,000, and a salvage value of $20,000 at the end of its useful life of 6 years. Assuming a discount rate of 9.0%, what is the minimum acceptable revenue to justify taking this project? A 1.01% B $333 C $2704 D $767 E $107049. Two machinery alternatives are described below. Complete the table below, assuming an interest rate of 6% and a useful lifetime of 8 years. Alt. 1: The initial purchase price of the machine is $25,000. The salvage value at the end of the useful life will be $5000. Maintenance costs are $2000 for the first year and remains same for the rest of the life. Alt.2 2: The machine is leased for an initial payment of $2000 plus annual payments of $3500. There is no salvage value. A maintenance contract is purchased for a single payment of $10,000 at the start of the lease period. Alt 2 PWB PWC NPW State selection criteria and make decision on what alt. to select?Two alternatives are being considered for installation. Which should be selected based on an interest rate of 5.6% per year ? Alternative A Alternative B First Cost, $ 135,000 462,000 Annual Operating Cost, $/yr 76,000 34,600 Salvage value, $ 71,200 n/a Life, years 9 ∞
- An equipment was purchased now at P10,000,000.00 prevailing interest rate is 10% per year. Solve the following cases capitalized cost: Answer no. 3 only Solve for case 1 if the projected maintenance cost will total P5,000,000.00 for 10 years. Use 10% as worth of money or interest rate. Solve for case 2 if the machine on item 1.1 is to be replaced every end of 10 years at 10% worth of money. Salvage cost is zero. Solve for case 3 using the above value on case 1 and 2 at 10%A new robot has a first cost of $380,000, and an annual operating cost of $88,000 in years 1 and 2, increasing by $10000 per year thereafter. The salvage value of the system is $25,000 regardless of when the system is retired within its maximum useful life of 5 years. Using a MARR of 14% per year, determine the ESL and the respective AW value of the system ESL: a) 1 year b) 4 years c) 5 years d) 3 years AW value of system: a) $204,860 b) $336,284 c) $97,953 d) $496,200Required Information [The following information applies to the questions displayed below.] Project A requires a $365,000 initial investment for new machinery with a five-year life and a salvage value of $42,000. The company uses straight-line depreciation. Project A is expected to yield annual net income of $25,300 per year for the next five years. Compute Project A's payback period. Choose Numerator: Payback Period 7 Choose Denominator: = Payback Period Payback period =
- A company is considering two alternatives with regards to equipment which it needs. The alternatives are as follows: Alternative A: Purchase Cost of Equipment 703,668700,000 Salvage Value 100,454100,000 Daily operating cost 501500 Economic life, years 10 Alternative B: Rental at 1,5751,500 per day. At 18% interest, how many days per year must the equipment be in use if Alternative A is to be chosen.QBS company wishes to replace its current equipment that was purchased 8years ago with the newer technology. System A will have a first cost of P1.6M, an operating cost of P70,000 per year, and a salvage value of P400,000 after its 4-year life. System B wll have a first cost of P2.1M, an operating cost of P50,000 the first year with an expected increase of P3,000 per year thereafter, and no salvage value after its 8-year life. On the basis of a future worth analysis at an interest rate of 12% per year, write the ANSWER for ALTERNATIVE A: Blank 1 ANSWER for ALTERNATIVE B: Blank 2onsider the following financial informationabout a retooling project at a computer manufacturing company:• The project costs $2.5 million and has a five-yearservice life.• The retooling project can be classified as sevenyear property under the MACRS rule.• At the end of the fifth year, any assets held for theproject will be sold. The expected salvage valuewill be about 10% of the initial project cost.• The firm will finance 40% of the project moneyfrom an outside financial institution at an interestrate of 10%. The firm is required to repay the loanwith five equal annual payments.• The firm’s incremental (marginal) tax rate on theinvestment is 35%.• The firm’s MARR is 18%.With the preceding financial information,(a) Determine the after-tax cash flows.(b) Compute the annual equivalent worth for thisproject.
- Oriental Corporation has gathered the following data on a proposed investment project: Investment in depreciable equipment $ 450,000 $ 90,000 Annual net cash flows Life of the equipment 10 years Salvage value Discount rate 53 $ 0 7% The company uses straight-line depreciation on all equipment. Assume cash flows occur uniformly throughout a year except for the initial investment. The payback period for the investment would be: (Round your answer to 1 decimal place.) Multiple Choice 0.2 years < Prev 5 of 5 Lavext a nere to search acer 立Required Information [The following information applies to the questions displayed below.] Project A requires a $365,000 initial investment for new machinery with a five-year life and a salvage value of $42,000. The company uses straight-line depreciation. Project A is expected to yield annual net income of $25,300 per year for the next five years. Compute Project A's accounting rate of return. Choose Numerator: Accounting Rate of Return I Choose Denominator: = Accounting Rate of Return Accounting rate of returnTwo pumps are being considered for purchase for a service life of 10 years. Interest rate is 5%. Alternatives Pump 1 Pump 2 Initial Cost $60,000 $75,000 Estimated salvage value at end of useful life $10,000 $12,000 Useful Life 6 years 12 years Estimated market value, end of 10-year $12,000 $15,000 Apply the present worth technique, which pump should be considered? Solution: 1. Neither input nor output is the same, calculate the net present worth (NPW) 2. NPW;: o Initial cost: PW= o Equivalent PW for salvage and replacement together: PW= k; o Cash flow at the end of 10 years, PW= k; o Thus NPW = k. 3. NPW2: o Initial cost: PW= o Equivalent PW for salvage and replacement together: PW= k; o Cash flow at the end of 10 years, PW= k; o Thus NPW2= k. 4. Hence use
