Q5 The single-line diagram of a three-phase power system is shown in Figure Q5a, with equipment ratings given in Table Q5a. (a) (b) G₁ G₂ G3 G4 T₁ T₂ T3 TA Draw the zero, positive and negative-sequence reactance diagrams using 1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y) transformer phase shifts. Calculate the short circuit current as a result of three-phase bolted fault occurred at bus 1. Line 1-2 Line 1-3 Line 2-3 bus 1 0 Υ ΔΕ Line 1-3 Line 1-2 G₂ Line 2-3 bus 2 Da Figure 05a bus 3 Table Q5a T₂ KEY YE my 1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u. 1000 MVA, 15 kV, X₁-X2-0.20 p.u., Xo = 0.10, p.u. 500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u. 750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u. 1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u. 1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u. 500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u. 750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u. Χ = 50 Ω, Χρ = 150 Ω. X = 40 Ω, X = 100 Ω. Χρ = 40 Ω, Χρ = 100 Ω.
Q5 The single-line diagram of a three-phase power system is shown in Figure Q5a, with equipment ratings given in Table Q5a. (a) (b) G₁ G₂ G3 G4 T₁ T₂ T3 TA Draw the zero, positive and negative-sequence reactance diagrams using 1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y) transformer phase shifts. Calculate the short circuit current as a result of three-phase bolted fault occurred at bus 1. Line 1-2 Line 1-3 Line 2-3 bus 1 0 Υ ΔΕ Line 1-3 Line 1-2 G₂ Line 2-3 bus 2 Da Figure 05a bus 3 Table Q5a T₂ KEY YE my 1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u. 1000 MVA, 15 kV, X₁-X2-0.20 p.u., Xo = 0.10, p.u. 500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u. 750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u. 1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u. 1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u. 500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u. 750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u. Χ = 50 Ω, Χρ = 150 Ω. X = 40 Ω, X = 100 Ω. Χρ = 40 Ω, Χρ = 100 Ω.
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.53P: The ratings of a three-phase, three-winding transformer are Primary: Y connected, 66kV,15MVA...
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Question
Transcribed Image Text:Q5
The single-line diagram of a three-phase power system is shown in Figure Q5a, with
equipment ratings given in Table Q5a.
(a)
(b)
G₁
G₂
G3
G4
T₁
T₂
T3
TA
Draw the zero, positive and negative-sequence reactance diagrams using
1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y)
transformer phase shifts.
Calculate the short circuit current as a result of three-phase bolted fault
occurred at bus 1.
Line 1-2
Line 1-3
Line 2-3
bus 1
0
Υ ΔΥ
Line 1-3
Line 1-2
G₂
Line 2-3
bus 2
Da
Figure 05a
bus 3
Table Q5a
T₂
KEY
YE
my
1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u.
1000 MVA, 15 kV, X₁-X₂-0.20 p.u., Xo = 0.10, p.u.
500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u.
750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u.
1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u.
1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u.
500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u.
750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u.
Χ = 50 Ω, X = 150 Ω.
Χ = 40 Ω, Χρ = 100 Ω.
Χρ= 40 Ω, Χρ = 100 Ω.
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