internet Checksum. Consider the two sixteen bit numbers: 10110100 01000110 00001000 01101110 Compute the Internet Checksum of these two values Enter the 2 bytes each as an 8-bit number with only O's and 1's, and make a single blank space between the two 8-bit numbers (e.g., 01010101 00101000).
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- Consider the two sixteen bit numbers: 10110100 01000110 11001000 01101110 ↳ Compute the Internet Checksum of these two values Enter the 2 bytes each as an 8-bit number with only O's and 1's, and make a single blank space between the two 8-bit numbers (e.g., 01010101 00101000).3.3-1. Internet Checksum. Consider the four sixteen bit numbers: 10110100 01000110 01001001 01101111 10110111 01100111 01001011 11101111 Compute the Internet Checksum of these two values Enter the 2 bytes each as an 8-bit number with only O's and 1's, and make a single blank space between the two 8-bit numbers (e.g., 01010101 00101000). [Note: Use XOR function, as I explained in class to find the checksum field value.]Internet Checksum. Consider the two sixteen bit numbers: 10110100 01000110 01001000 01101111 Compute the Internet Checksum of these two values Enter the 2 bytes each as an 8-bit number with only O's and 1's, and make a single blank space between the two 8-bit numbers (e.g., 01010101 00101000).
- n alternative to hexadecimal notation for representing bit patterns is dotted decimal notation in which each byte in the pattern is represented by its base ten equivalent. In turn, these byte representations are separated by periods. For example, 12.5 represents the pattern 0000110000000101 (the byte 00001100 is represented by 12, and 00000101 is represented by 5), and the pattern 100010000001000000000111 is represented by 136.16.7. Represent each of the following bit patterns in dotted decimal notation. 0000111100001111 001100110000000010000000 0000101010100000Suppose the sender wants to send the word Midterm. In ASCII the seven characters are coded as 1101001 1001101 1100100 1110100 1100101 1110010 1101101 Calculate the row parity bit and column parity bits of data and also show the data to be sent after applying redundancy.For this problem we will use a hypothetical floating-point representation that is similar to IEEE-754. It uses 12 bits total, consisting of 1 sign bit, 5 exponent bits, and 6 mantissa bits. Convert -14.125 to this format. Write the three portions of the number below as binary strings using the appropriate number of bits. Sign (1 bit): Exponent (5 bits): Mantissa (6 bits):
- 3. Implement a 32-bit subtraction of two numbers X and Y that are stored in memory as: X = (DS: 503H) MS byte of MS word (DS: 0502H) (DS: 0501H) (DS: 0500H) LS byte of MS byte of LS byte of MS word LS word LS word Y = (DS:0507H) (DS: 0506H) (DS: 0505H) (DS: 0504H) The result of X - Y is to be saved in the place where X is stored in memory.Consider a 16 bit FPN (floating point number). Here the exponent is in excess-63 form and mantissa is the fraction. Base of the system is 2. It is used to store (0.239) X 23. 1. In the above question, what will be the hexadecimal pattern, which denote the given value without normalization. Write the complete steps used for calculation. 2. What is the largest positive and the smallest positive number stored in the 16-bit register of the FPN? Cleary explain what will be the values of mantissa and exponent in the case of largest and smallest positive number with proper justification.A binary code uses ten bits to represent each of the ten decimal digits. Each digit is assigned a codeof nine 0’s and a 1. The code for digit 6, for example, is 0001000000. Determine the binary code forthe remaining decimal digits.
- Convert the decimal number (1249)10 to its equivalent binary, hexadecimal, and octal (base 8). What is the minimum number of bits that you need for each base? (You can show decimal numbers using d: 1249d = (1249)10), and h for hexadecimal numbers, and b for binary numbers). Extend the sign of this number, and convert it to a 32-bit binary.Represent the binary representation of a float type to integer type. Single precision float (32-bit length) is represented in IEEE754 format: 1 bit of sign, 8 for exponent plus bias of 127, and 23 for the mantissa. Example: * 85.125 is [101 0101.001] in binary and this would be [1.0101 0100 1 x 2^6] in scientific notation of base 2. * Our sign bit will be [0] (positive), exponent+bias is [1000 0101] (6 + 127 = 133), and mantissa of [0 1010 1001000...] (whole is omitted and zeroes are added to the right until its length is 23). * Merging this will be [0100 0010 1010 1010 0100 0000 0000 0000] which is equivalent as 1118453760 in integer. * Therefore, binary of 85.125 in float is 1118453760 in integer. Input A single line containing a float type non-positive number. 85.125Output A single line containing the integer representation of float type binary. 1118453760What is the Huffman code for a string consisting entirely of letters from a two-character alphabet? Give an example of the most bits that might be utilised in a Huffman code for an N-character string whose characters are all from a two-character alphabet.