Please indicate if the arrows represent the movement of one electron or a pair of electrons! H3CH3CCH3Submit AnswerHBrElectrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on thehydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This stepfollows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the mosthydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift ofeither a neighboring hydride or methyl group can occur prior to the last step in order to form a more stablecarbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give theneutral product.Draw curved arrows to show the movement of electrons in this step of the mechanism.Arrow-pushing InstructionsAOC XTCH3 H-BrمحمدRetry Entire GroupCH3H3CH8 more group attempts remainingCH3Br H3CH3C07H3CH3CCH3CH₂CH3C→XTHBrCH3Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on thehydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This stepfollows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the mosthydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift ofeither a neighboring hydride or methyl group can occur prior to the last step in order to form a more stablecarbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give theneutral product.Draw curved arrows to show the movement of electrons in this step of the mechanism.Arrow-pushing InstructionsBrH3CCH₂ H-BrCH3CH3H3C.H3CCH3CH3Br

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H3C CH3 Arrow-pushing Instructions H3C H3C Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp² carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the last step in order to form a more stable carbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give the neutral product. Draw curved arrows to show the movement of electrons in this step of the mechanism. NOC XT Submit Answer HBr CH3 H-Br Br Retry Entire Group CH3 H3C H 8 more group attempts remaining CH3

H3C CH3 Arrow-pushing Instructions H3C H3C Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp² carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the last step in order to form a more stable carbocation. In the final step of the reaction, nucleophilic bromide adds to the carbocation to give the neutral product. Draw curved arrows to show the movement of electrons in this step of the mechanism. NOC XT Submit Answer HBr CH3 H-Br Br Retry Entire Group CH3 H3C H 8 more group attempts remaining CH3

Pushing Electrons

4th Edition

ISBN:9781133951889

Author:Weeks, Daniel P.

Publisher:Weeks, Daniel P.

Chapter3: Mechanisms

Section: Chapter Questions

Problem 16EQ

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