For a highway curve with D₁ = 5°00', I = 20°30', and Pl station = 63+ 25.53 ft, calculate the requested values to lay out the circular curve at full stations (100 ft). Part F Tabulate stations, deflection angles, and incremental chords to lay out the curve at full stations (100 ft). Express angles in degrees to four decimal places; express first station numbers as integers; second station numbers and chord lengths should be expressed in feet to two decimal places. The PC station should be placed at the bottom of the table. Submit Station + Chord Defl. Increment Defl. Angle ° + 00.00 2.500 00.00 2.500 + 00.00 2.500 00.00 Previous Answers Request Answer × Incorrect; Try Again; 5 attempts remaining

A simple curve has a radius of 80 meters and its angle of intersection is 64 degrees. The curve has six stations (PC, 1, 2, 3, 4, and PT) and the stationing of PI is 5+105. What is the stationing of PC? A 5+105 B) 5+055.01 c) 5+323.45 4+995.34 None of the above

Given broken line AB = 57.6 m., BC = 91,5 m. and CD = 91.5 m. arranged as shown. A reverse curve is to connect these three lines thus forming the center line of a new road. %3D a) Find the length of the common radius of the reverse curve, b) Find the total length of the reverse curve, CIf the P.C. is at Sta. 10+000, what are the stationing of P.R.C, and P.T. Solu tion: a) T, =Rtan 11 %3D T = R tan 32 T+T = 91.5 91.5 m R (tan 11 + tan 32 ) = 91.5 PT R = 111.688 m. 82 RI IR 7,5 7.5 64 56.7 G'16

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For a highway curve with Da=5∘00′, I=20∘30′, and PI station=63+25.53ft, calculate the requested values to lay out the circular curve at full stations (100 ft). Tabulate stations, deflection angles, and incremental chords to lay out the curve at full stations (100 ft). Express angles in degrees to four decimal places; express first station numbers as integers; second station numbers and chord lengths should be expressed in feet to two decimal places. The PC station should be placed at the bottom of the table.   Radius - 1,145.92ft Curve Length = 410 ft Tangent Distant = 207.22 ft Middle Ordinate = 18.29 ft External Distance = 18.58 ft   Please show me the steps of what I need to do to fill the chart with the information I already have. See picture for chart.

A simple circular horizontal curve has a radius of 5200 ft and an intersection angle 35°. The station of the Pl is 260+75. What is the station of the PT? 237+65 O 244+35.4 O 276+12 O 277+14.6 O 292+51.5

Please show illustrations if possible. Three tangent lines AB, BC, and CD of a traverse have azimuths of 228°, 253°30’, and 315°18’ respectively. The station of B is 10+585 and that of C is 10+885. A proposed highway curve is to connect these three tangents. a) Compute the radius of the simple curveb) Compute the stationing of the PCc) Compute the length of the curve from PC

Compute for the length of curve A line of levels was taken at given points on the existing surface as part of a road reconstruction project. Station Points Elevation 2+075 A 104.63m 2+225 B 109.13m 2+550 C 107.29m 2+725 D 103.79m

On a rail road line, two tangents that intersect at station 10 + 243 so as to form an angle of 36°28′ are to be connected by a compound curve consisting of two simple curves. The simple curve beginning at the P.C. which is at station 10 + 163 is to be 4° curve whose degree is based on a 20m chord and is to have a central angle of 17°. Using chord basis:a. What should be the radius of the other simple curve that ends at the P.T.?b. Compute the stationing of P.C.C.

Q3: A circular curve having coordinates given in the Table. The chainage/station of PC is 3+40m. Calculate: 1. The curve length (L), Chord (C), Tangent (T), Radius (R) and deflection angle. 2. Coordinates (Easting and Northing) of station 4+60 on the curve. Point PC PI PT Easting (m) 250.031 275.316 380.375 Northing (m) 448.17 550.172 547.67