d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42) through (12.44), and take K = 1.4 and 8' = 0.60'.] e. The allowable load of the pile (use FS = 4). 3 m 3 m 15 m 381 mm Groundwater table 15.7 kN/m³ Y o' = 32° c' = 0 Ysat 18.2 kN/m³ $' = 32° c' = 0 Ysat = 19.2 kN/m³ $' = 40° c' = 0

Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter12: Pile Foundations
Section: Chapter Questions
Problem 12.2P: A 20 m long concrete pile is shown in Figure P12.2. Estimate the ultimate point load Qp by a....
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12.7 A driven closed-ended pile, circular in cross section, is
shown in Figure P12.7. Calculate the following.
a. The ultimate point load using Meyerhof's procedure.
b. The ultimate point load using Vesic's procedure. Take
Irr = 50.
c. An approximate ultimate point load on the basis of parts
(a) and (b).
d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42)
through (12.44), and take K = 1.4 and 8' = 0.60'.]
e. The allowable load of the pile (use FS = 4).
3 m
3 m
15 m
381 mm
FIGURE P12.7
Groundwater
table
=
Y
$' = 32°
c' = 0
15.7 kN/m³
=
Ysat 18.2 kN/m³
$' = 32°
c' =0
Ysat
19.2 kN/m³
$' = 40°
c' = 0
Transcribed Image Text:12.7 A driven closed-ended pile, circular in cross section, is shown in Figure P12.7. Calculate the following. a. The ultimate point load using Meyerhof's procedure. b. The ultimate point load using Vesic's procedure. Take Irr = 50. c. An approximate ultimate point load on the basis of parts (a) and (b). d. The ultimate frictional resistance Q₁. [Use Eqs. (12.42) through (12.44), and take K = 1.4 and 8' = 0.60'.] e. The allowable load of the pile (use FS = 4). 3 m 3 m 15 m 381 mm FIGURE P12.7 Groundwater table = Y $' = 32° c' = 0 15.7 kN/m³ = Ysat 18.2 kN/m³ $' = 32° c' =0 Ysat 19.2 kN/m³ $' = 40° c' = 0
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