D) 1001+0011 E) 7E+1F tion 3: , 1000 + 1001 (using BCD for both) , (1100011100) find the second complement

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Solution D and E Digital Electronics
Question 2: Do as required:
A) (100110)2 = (?)10
B) (38)10 (2)16
C) (26)16
(?)10
D) 10010011
E) 7E+1F
Question 3:
=
D
, (11000) = (?)10
, (24)10 = (?)16
, (18)16 = (?)10
1000+ 1001 (using BCD for both)
, (1100011100), find the second complement
Transcribed Image Text:Question 2: Do as required: A) (100110)2 = (?)10 B) (38)10 (2)16 C) (26)16 (?)10 D) 10010011 E) 7E+1F Question 3: = D , (11000) = (?)10 , (24)10 = (?)16 , (18)16 = (?)10 1000+ 1001 (using BCD for both) , (1100011100), find the second complement
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