Complete the function below such that below10 that takes in a list of integers, and returns a list of only the elements in the original that were less than 10.
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- Complete the function odd_even that classifies an number as either 'odd' or 'even' and the function classify that takes in a list and applies odd_even to all elements in the list. def odd_even(x): """Classify a number as odd or even. >>> odd_even (4) 'even' >>> odd_even (3) 'odd' III|II "*** YOUR CODE HERE ***" def classify(s): Classify all the elements of a sequence as odd or even >>> classify ([0, 1, 2, 4]) ['even', 'odd', 'even', 'even'] III "*** YOUR CODE HERE ***"***python only*** Write a function votes_by_race() which takes a list of dicts as a parameter and returns a dict. For example, given the following list: votes = [{'for': 'A, 'age': 35, 'race': 'w'}, {'for': 'B', 'age': 40, 'race': 'b'}, {'for': 'B', 'age': 20, 'race': 'b'}, {'for': 'A', 'age': 30, 'race': 'a'}, {'for': 'A', 'age': 41, 'race': 'w'}, ] The call votes_by_race(votes) should return the following dict:{"White": 2, 'Black': 2, 'Asian': 1, "Hispanic': 0}Write a function that returns the greatest common divisor (GCD) of integers in a list. Use the following function header:def gcd(numbers):Write a test program that prompts the user to enter five numbers, invokes the function to find the GCD of these numbers, and displays the GCD.
- Exercise, maxCylinderVolume F# system function such as min or methods in the list module such as List.map are not allowed Write a function maxCylinderVolume that takes a list of floating-point tuples that represent dimensions of a cylinder and returns the volume of the cylinder that has the largest volume. Each tuple has two floating point values that are both greater than zero. The first value is the radius r and the second value is the height h. The volume of the cylinder is computed using ??2h. The value π is represented in F# with System.Math.PI. If the list is empty, return 0.0. Examples: > maxCylinderVolume [(2.1, 3.4); (4.7, 2.8); (0.9, 6.1); (3.2, 5.4)];;val it : float = 194.3137888> maxCylinderVolume [(0.33, 0.66)];;val it : float = 0.2257988304int* p: int a[3]{1, 2, 3}; p = a; What is the value of *(p+2)?16-Write a function called find_integer_with_most_divisors that receives a list of integers and returns the integer from the list with the most divisors .In the event of a tie, the first case with the most divisors returns .For example: If the list looks like this: [8, 12, 18, 6] In this list, the number 8 has four divisors, which are ;[1,2,4,8] :The number 12 has six divisors, which are ;[1,2,3,4,6,12] :The number 18 has six divisors, which are ;[1,2,3,6,9,18] :And the number 6 has four divisors, which are : [1,2,3,6]Note that both items 12 and 18 have the maximum number of divisors and are equal in number of divisors (both have 6 divisors) .Your function must return the first item with the maximum number of divisors ;Therefore it must return the following value: 12
- Write the code of the following functions: def fillX(pointsX,lowerLimit, upperLimit): This function receives a list pointsX and returns the same list with values between loverLimit and upperLimit. There are number of them.Q1:Write a function that returns a new list by eliminating theduplicate values in the list. Use the following function header:def eliminateDuplicates(lst):Write a test program that reads in a list of integers, invokes the function,and displays the result. Here is the sample run of the program Enter ten numbers: 2 3 2 1 6 3 4 5 2The distinct numbers are: 1 2 3 6 4 5 Q2:Write a program that reads in your Q1 Pythonsource code file and counts the occurrence of each keyword in the file.Your program should prompt the user to enter the Python source code filename. This is the Q1: code: def eliminateDuplictes(lst):newlist = [] search = set() for i in lst: if i not in search: newlist.append(i) search.add(i) return newlist a=[] n= int(input("Enter the Size of the list:")) for x in range(n):item=input("\nEnter element " + str(x+1) + ":") a.append(item) result = eliminateDuplictes(a) print('\nThe distinct numbers are: ',"%s" % (' '.join(result)))] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Python
- Count dominators def count_dominators(items): An element of items is said to be a dominator if every element to its right (not just the one element that is immediately to its right) is strictly smaller than it. By this definition, the last item of the list is automatically a dominator. This function should count how many elements in items are dominators, and return that count. For example, dominators of [42, 7, 12, 9, 13, 5] would be the elements 42, 13 and 5. Before starting to write code for this function, you should consult the parable of "Shlemiel the painter" and think how this seemingly silly tale from a simpler time relates to today's computational problems performed on lists, strings and other sequences. This problem will be the first of many that you will encounter during and after this course to illustrate the important principle of using only one loop to achieve in a tiny fraction of time the same end result that Shlemiel achieves with two nested loops. Your workload…Write a function reverse_iter_for that takes a list and returns a new list that is the reverse of the original using a for loop. You should not need any indexing notation. def reverse_iter_for(lst): """Returns the reverse of the given list. >>> reverse_iter_for([1, 2, 3, 4]) [4, 3, 2, 1] TELEEL "*** YOUR CODE HERE ***" Complete the function reverse_iter_while that behaves identically to reverse_iter_for but is implemented as using a while loop. You may use indexing or slicing notation. Do not use 1st [::-1] ! def reverse_iter_while(lst): """Returns the reverse of the given list. >>> reverse_iter_while([1, 2, 3, 4]) [4, 3, 2, 1] rev_lst, i = [], 0 while i < len(lst): "*** YOUR CODE HERE ***"Write a function called remove_odd that takes a list of numbers that have both even and odd numbers mixed.# Function should remove all the odd numbers and return a compact list which only contains the even numbers. Example1: Function Call:remove_odd ([21, 33, 44, 66, 11, 1, 88, 45, 10, 9])Output:[44, 66, 88, 10]