Calculate the standard enthalpy of formation of the M20(s) metal oxide (AHf in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 107 kJ/mol First ionization energy of M = + 488 kJ/mol Lattice enthalpy of M20(s) = -2108 kJ/mol

General Chemistry - Standalone book (MindTap Course List)
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Chapter9: Ionic And Covalent Bonding
Section: Chapter Questions
Problem 9.133QP
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Calculate the standard enthalpy of formation of the M20(s) metal oxide (AHe in
kJ/mol) using the following data:
Bond dissociation enthalpy of O2(g) = +498 kJ/mol
First electron affinity of O = -141 kJ/mol
Second electron affinity of O = +744 kJ/mol
Enthalpy of sublimation of M
= + 107 kJ/mol
First ionization energy of M
= + 488 kJ/mol
Lattice enthalpy of M20(s) = -2108 kJ/mol
Transcribed Image Text:Calculate the standard enthalpy of formation of the M20(s) metal oxide (AHe in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 107 kJ/mol First ionization energy of M = + 488 kJ/mol Lattice enthalpy of M20(s) = -2108 kJ/mol
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