Calculate AG for the reaction given below if the partial pressure of NO₂ is 0.220 atm and the partial pressure of N₂O4 is 0.428 atm. 2NO2(g) = N₂O4(8) AG 298 of this reaction is -5.40 kJ per mole of N₂O. T = 298K, R = 8.314 J.mol-¹.K-1 Note: Round you answer to 2 decimal places. AG = i kJ mol-1 Where does the system stand relative to equilibrium? O The system is at equilibrium, so that the reaction will not move. O The equilibrium shifts to products. O The equilibrium shifts to reactants.
Calculate AG for the reaction given below if the partial pressure of NO₂ is 0.220 atm and the partial pressure of N₂O4 is 0.428 atm. 2NO2(g) = N₂O4(8) AG 298 of this reaction is -5.40 kJ per mole of N₂O. T = 298K, R = 8.314 J.mol-¹.K-1 Note: Round you answer to 2 decimal places. AG = i kJ mol-1 Where does the system stand relative to equilibrium? O The system is at equilibrium, so that the reaction will not move. O The equilibrium shifts to products. O The equilibrium shifts to reactants.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter17: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 118CP: Consider the reaction H2(g)+Br2(g)2HBr(g) where H = 103.8 kJ/mol. In a particular experiment, equal...
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![Calculate AG for the reaction given below if the partial pressure of NO₂ is 0.220 atm and the partial pressure of N₂O4 is 0.428 atm.
2NO2(g) N2O4(8)
AG 298 of this reaction is -5.40 kJ per mole of N₂O. T = 298K, R = 8.314 J.mol-¹.K-¹
Note: Round you answer to 2 decimal places.
AG=
kJ mol-1
Where does the system stand relative to equilibrium?
The system is at equilibrium, so that the reaction will not move.
O The equilibrium shifts to products.
O The equilibrium shifts to reactants.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff684c535-6972-4ddd-8def-954d1e45ba79%2F1d925f16-159a-4fbe-9a34-36020c30a246%2Fd2u2ela_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate AG for the reaction given below if the partial pressure of NO₂ is 0.220 atm and the partial pressure of N₂O4 is 0.428 atm.
2NO2(g) N2O4(8)
AG 298 of this reaction is -5.40 kJ per mole of N₂O. T = 298K, R = 8.314 J.mol-¹.K-¹
Note: Round you answer to 2 decimal places.
AG=
kJ mol-1
Where does the system stand relative to equilibrium?
The system is at equilibrium, so that the reaction will not move.
O The equilibrium shifts to products.
O The equilibrium shifts to reactants.
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