At least one of the answers above is NOT correct. Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter 1.) I с I C I I 1. For all n > 2,8 < 22, and the series 2Σ converges, so by the Comparison Test, the series Σ converges, so by the Comparison Test, the series Σ converges. converges. 2. For all n> 1, ¹¹², < 6-1³ and the series 3. For all n>1 arctan(n) converges. 72³ In(n) 15, and the series converges, so by the Comparison Test, the series converges. nln(n) converges. 4. For all n > 1 5. For all n > 1, 6. For all n > 2, arctan(n) 72² In(n) 72²<

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 68E
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At least one of the answers above is NOT correct.
Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement,
enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you
must enter I.)
|
C
I
C
I
I
1. For all n > 2, </ , and the series 2 Σ converges, so by the Comparison Test, the series
2. For all n > 1,6</
, and the series
3. For all n > 1,
arctan(n)
72³
In(n)
23, and the series
4. For all n > 1
5. For all n > 1, nln(n) </2, and the series 2 Σ diverges, so by the Comparison Test, the series Σnin(n) diverges.
converges, so by the Comparison Test, the series > converges.
In(n)
6. For all n > 2,
In(n)
7²
2, and the series
7²
<
15, and the series
converges, so by the Comparison Test, the series
converges.
converges.
arctan(n)
nª
converges, so by the Comparison Test, the series >
converges, so by the Comparison Test, the series > converges.
In(n)
7²
converges
Transcribed Image Text:At least one of the answers above is NOT correct. Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter I.) | C I C I I 1. For all n > 2, </ , and the series 2 Σ converges, so by the Comparison Test, the series 2. For all n > 1,6</ , and the series 3. For all n > 1, arctan(n) 72³ In(n) 23, and the series 4. For all n > 1 5. For all n > 1, nln(n) </2, and the series 2 Σ diverges, so by the Comparison Test, the series Σnin(n) diverges. converges, so by the Comparison Test, the series > converges. In(n) 6. For all n > 2, In(n) 7² 2, and the series 7² < 15, and the series converges, so by the Comparison Test, the series converges. converges. arctan(n) nª converges, so by the Comparison Test, the series > converges, so by the Comparison Test, the series > converges. In(n) 7² converges
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