A box with a square base and open top must have a volume of 296352 cm³. A(x) We wish to find the dimensions of the box that minimize the amount of material used. Step 1: Find a formula for the surface area of the box in terms of only x, the length of one side of the square base. Hint: use the volume formula to express the height, y of the box in terms of x, and then substitute this into the surface area formula. Simplify your formula as much as possible. = x //////// Step 2: Find the derivative, A'(x). A'(x) = /////// x Find the critical values, that is solve A'(x) = 0 for x. Hint: Multiply both sides for ² The critical value(s) are x = Y We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = and then x = y = Evaluate A"(x) at the x-value you gave above. The dimensions of the box that minimizes the volume is Part 3 of 3

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter61: Areas Of Circles, Sectors, And Segments
Section: Chapter Questions
Problem 50A
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Question
A box with a square base and open top must have a volume of 296352 cm³.
A(x)
We wish to find the dimensions of the box that minimize the amount of material used.
Step 1: Find a formula for the surface area of the box in terms of only x, the length of one side of the
square base.
Hint: use the volume formula to express the height, y of the box in terms of x, and then substitute this
into the surface area formula.
Simplify your formula as much as possible.
=
x
////////
//////////
Step 2: Find the derivative, A'(x).
A'(x) =
///////
x
Find the critical values, that is solve A'(x)
Hint: Multiply both sides for x²
The critical value(s) are x =
y
=
and then
X =
y =
We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the
second derivative test. Find A"(x).
A"(x)
=
Evaluate A"(x) at the x-value you gave above.
0 for x.
The dimensions of the box that minimizes the volume is
Part 3 of 3
Transcribed Image Text:A box with a square base and open top must have a volume of 296352 cm³. A(x) We wish to find the dimensions of the box that minimize the amount of material used. Step 1: Find a formula for the surface area of the box in terms of only x, the length of one side of the square base. Hint: use the volume formula to express the height, y of the box in terms of x, and then substitute this into the surface area formula. Simplify your formula as much as possible. = x //////// ////////// Step 2: Find the derivative, A'(x). A'(x) = /////// x Find the critical values, that is solve A'(x) Hint: Multiply both sides for x² The critical value(s) are x = y = and then X = y = We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = Evaluate A"(x) at the x-value you gave above. 0 for x. The dimensions of the box that minimizes the volume is Part 3 of 3
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Follow-up Question
A box with a square base and open top must have a volume of 296352 cm³.
X
X
Y
We wish to find the dimensions of the box that minimize the amount of material used.
Step 1: Find a formula for the surface area of the box in terms of only x, the length of one side of the
square base.
Hint: use the volume formula to express the height, y of the box in terms of x, and then substitute this
into the surface area formula.
Simplify your formula as much as possible.
A(x) =
//////////
Step 2: Find the derivative, A'(x).
A'(x) =
Find the critical values, that is solve A'(x) = 0 for x .
Hint: Multiply both sides for x²
The critical value(s) are x =
and then
We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the
second derivative test. Find A"(x).
A"(x) =
Evaluate A"(x) at the x-value you gave above.
Transcribed Image Text:A box with a square base and open top must have a volume of 296352 cm³. X X Y We wish to find the dimensions of the box that minimize the amount of material used. Step 1: Find a formula for the surface area of the box in terms of only x, the length of one side of the square base. Hint: use the volume formula to express the height, y of the box in terms of x, and then substitute this into the surface area formula. Simplify your formula as much as possible. A(x) = ////////// Step 2: Find the derivative, A'(x). A'(x) = Find the critical values, that is solve A'(x) = 0 for x . Hint: Multiply both sides for x² The critical value(s) are x = and then We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = Evaluate A"(x) at the x-value you gave above.
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