A ball is thrown straight down from the top of a 434-foot building with an initial velocity of -18 feet per second. Use the position function below for free-falling objects. s(t) = -16t2 + v0t + s0 What is its velocity after 2 seconds? v(2) = ft/s What is its velocity after falling 198 feet? v = ft/s
Rate of Change
The relation between two quantities which displays how much greater one quantity is than another is called ratio.
Slope
The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:
A ball is thrown straight down from the top of a 434-foot building with an initial velocity of -18 feet per second. Use the position function below for free-falling objects.
v(2) = ft/s
What is its velocity after falling 198 feet?
v = ft/s
Given position function of the ball
s(t) = - 16t2 + v0t + s0
Height of the building or initial position s0 =434 foot
Initial velocity v0 = - 18 feet/second
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