8. How long it takes for the signal to get from the output of the Modulator/transmitter, point to the input of the 2-way splitter, point (3 9. Po from Amplifier 1, point (5 in dBm. in ns.
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- d) A regulator as shown in Figure 4 has an input voltage, Vs 12 V. The duty cycle, k = 0.35 and the switching frequency is 30 kHz. It also has an inductance, L= 200 µH, filter capacitance, C = 440 µF. The average load current, la = 1.25 A. Determine the; i. average output voltage, Va. ii. peak-to-peak output ripple voltage, AVc. iii. peak-to-peak output ripple current of inductor, AI. iv. peak current of the transistor, Ip. v. critical values of L and C. vi. critical values of L and C if Vs is increased to 14 V. Estimate the change in percentage for the critical values of L and C. V, Load V V G Figure 43. Consider the voltage signal v(t) below as the reference. Express the voltage source in peak, peak-peak and effective value VRMs. Express the magnitude of the current in terms of its' effective value IRMS. Approximate the frequency f of the voltage source. Approximate the phase angle 0 from the reference voltage source to the current ( 12.5 Af f= e= 7.5- -6 V peak = 10- 2.5 IRMS = -21 VRMS= 5 -10 Vpeak-peak = v (t) 12 18 24 30 36 42 48 54 60 i(t) t(us) The circuit drawing this current from the voltage source could be more (circle one): Capacitive OR InductiveFor a three stage-system with an input power P(in)=-35dBm and power gains of the three stages as Ap1=25 dB, Ap2=20dB, and Ap3 = -15dB, determine the output power P(out) in dBm and watts.
- i) Which type of compensator is used for feeding reactive power at the receiving end? Draw its block diagram. (ii) What is lag-lead compensator? Draw its circuit diagram and derive the expression for the transfer function of lag-lead compensator.Design (only the block diagram) an Armstrong indirectly FM modulator to generate an FM carrier with a carrier frequency of 98.1MHz and df (frequency deviation) =75kHz.A narrowband FM generator is available at a carrier frequency of 100 KHz and a (frequency deviation) df=10Hz.The stockroom has an oscillator with an adjustable frequency in the range of 10 to 11MHz.There are plenty of Frequency multipliers.Given that Iee :2mA and Vcee - 10v, determine Ri and Rc for the network in Figure 4. 1BV RI Re 1OMF Figure 4 31.2kn
- In the circuit given in the figure, Rk = 8.70Kohm, R1= 5277.50Kohm, R2=5722.50Kohm, R3 =4.31Kohm, R4=1.44Kohm, R5=24.60ohm, Ry=81.59Kohm, VCC-11.00V,VTN=2.79V, Kn= Since 4.56(mA/V*2), C1= 9.03uF, C2= 6.28uF, C3= 5.81uF, the undercut frequency of the circuit is Hz calculate it in terms of. When performing your operations, 2 steps will be taken after the point, according to the ±10% margin of error you found write the result In Hz. When typing the answer, the space in front of the value behind the font (Hz, KHz) V.b. values should not be written. Only numerical values should be entered. Dot as decimal bracket (.) should be used. An example illustration is given below. Let the value you found be 1.15K. You should write 1150.00 In the box. Let the value you found be 432.6. You should write 432.63 In the box. If the correct answer is X, the values entered in the December X + (X*10/100) (including limits) will be accepted. If X=50, the Dec between [45,55] will be accepted. 2 Rk www VS C1 +18…what is rms value of below signallll.What is the use of phase cross over frequency? How will you find it?
- 4) Listen A sinewave voltage is defined by an effective voltage of 2.82Vrms. Calculation of the amplitude Vpk is performed: By multiplying Vrms by 2/Pi (=0.637). By dividing Vrms by 1.41 (square root of 2). By multiplying Vrms by 1.41 (square root of 2). By dividing Vrms by 2/Pi (=0.637). Calculation cannot be done since we do not know the frequency of the signal. O None of these statements are true. prt sc 144Under what frequency range.( Need handwritten solution please otherwise downvote)7 Name the circuit shown below? Please justify the name with brief explanation of the working of this circuit. Page 3 of 6 Final Assignment If the input signal is a high frequency input signal to an AM receiver (very less amplitude) will this serve the purpose. If Yes Justify? If NO Justify and give the modification which will make it suitable for the above mentioned purpose. out RL