answers[Ans: total plate area  5433.4 m2 ; number of plates = 48 ] related slides included, show working to reach answers • The particle removal efficiency is given by:Apexp(-wete)n=1 - expThe effective drift velocity (w.) isproportional to:• average voltage through the dischargewires (Vavg)Corona discharge current (Ic)We & Vavg. IcSince Vavg. Ic = corona dischargepower: w₂x corona powerA major issue with ESPs is the significantelectrical demands for maintaining thecorona.Design component of the ESPNumber of plate channelswithin the ESP (N)Number of collector sectionsalong the length of the ESP (NS)Overall length of the ESP (L.)Total collection plate area (Ap)EquationNaNs=QguWZremoval efficiency (-)Electrostatic Precipitators (ESPs)Ꭱ ᏃLpA₁ = total collection plate areaQg = volumetric flowrate or waste gasW₂ = effective drift velocity.1Several components of the ESP must be sized, including the plates and housing:• Number of plate channels within the ESP• Number of collector sections along the length of the ESP• Overall length of the precipitator• Total collection plate areaAp = 2 Z Lp Ns Na0.80.60.40.20Note: example graph for academic purposes (not real data)0Ap/Qg = 50 s/mAp/Qg = 25 s/mAp/Qg = 12.5 s/m0.050.10.15effective drift velocity (m/s)Commentsu = waste gas velocityW = channel widthZ = plate height.0.213R = aspect ratio (= effective length /Z)L₂= length of one plateLs = spacing between plate sectionsLo = NsLp + (Ns − 1)Ls + Len + Lex Len= length of entrance sectionLex = length of exit sectionNote that the plates have two sides,hence the factor 214 3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat agas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of platesrequired, knowing the following:- The effective drift velocity is 6 cm/s;Each plate has a length of 6 m and a height of 10 m;-The ESP contains three sections and each section must have the same number of plates.[Ans: total plate area = 5433.4 m²; number of plates = 48 ]

Question

answers[Ans: total plate area  5433.4 m2 ; number of plates = 48 ] related slides included, show working to reach answers • The particle removal efficiency is given by:Apexp(-wete)n=1 - expThe effective drift velocity (w.) isproportional to:• average voltage through the dischargewires (Vavg)Corona discharge current (Ic)We & Vavg. IcSince Vavg. Ic = corona dischargepower: w₂x corona powerA major issue with ESPs is the significantelectrical demands for maintaining thecorona.Design component of the ESPNumber of plate channelswithin the ESP (N)Number of collector sectionsalong the length of the ESP (NS)Overall length of the ESP (L.)Total collection plate area (Ap)EquationNaNs=QguWZremoval efficiency (-)Electrostatic Precipitators (ESPs)Ꭱ ᏃLpA₁ = total collection plate areaQg = volumetric flowrate or waste gasW₂ = effective drift velocity.1Several components of the ESP must be sized, including the plates and housing:• Number of plate channels within the ESP• Number of collector sections along the length of the ESP• Overall length of the precipitator• Total collection plate areaAp = 2 Z Lp Ns Na0.80.60.40.20Note: example graph for academic purposes (not real data)0Ap/Qg = 50 s/mAp/Qg = 25 s/mAp/Qg = 12.5 s/m0.050.10.15effective drift velocity (m/s)Commentsu = waste gas velocityW = channel widthZ = plate height.0.213R = aspect ratio (= effective length /Z)L₂= length of one plateLs = spacing between plate sectionsLo = NsLp + (Ns − 1)Ls + Len + Lex Len= length of entrance sectionLex = length of exit sectionNote that the plates have two sides,hence the factor 214 3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat agas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of platesrequired, knowing the following:- The effective drift velocity is 6 cm/s;Each plate has a length of 6 m and a height of 10 m;-The ESP contains three sections and each section must have the same number of plates.[Ans: total plate area = 5433.4 m²; number of plates = 48 ]

Accepted Answer

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