25 20 1.0230- 1.0235 1.0240 1.0245 15 1.0250 л.0255 10 1.0260 1.0265 0- 31.5 32.0 32.5 33.0 33.5 1.0270 Salinity (ppt) FIGURE 25 Contour map of seawater density p(S, T) (kilograms per 34.0 cubic meter). 34.5 Temperature T (°C)
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Does water density appear to be more sensitive to a change in temperature at point A or point B?
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- Potential Temperature (°C) 20 15 10 0 33.5 1.004 1.025 34.0 1.0245 1.0255 A 1.0275 34.5 1.026 1.0265 1.027 1.028 35.0 Salinity (PPT) B 35.5 1.0285 1.029 36.0 36.5 Record your readings for Water Mass A. Temperature Salinity Density Save Values value value value |||||17. Match the following and choose the correct option. Column I Column II A. Molarity (M) Temperature р. B. Molality (m) q. Dilution C. Mole fraction (x) Volume г. D. Normality (N) Codes A C D (a) p, q, r q, r r 4, P (6) p, q, r q (c) 9, т (d) р, q р, 9, г р, т q, r p, qPotential Temperature (°C) 20 15 33.5 1.004 1.025 34.0 1.0245 1.0255 A 1.0275 34.5 1.026 1.0265 1.027 1.028 35.0 Salinity (PPT) B 35.5 1.0285 1.029 36.0 36.5 Record your readings for Water Mass B. Temperature Salinity Density Save Values value value value
- 3. HNO is formed by NO₂ as follows. Calculate HNO3 concentration in µg/m³ at 1 atm pressure and 22 °C temperature for NO₂ concentration of 1 ppm. (MWs of N = 14, O = 16 H = 1 g/mol, R 0.082 L.atm/mol.K) = OH (g) + NO2 (g) + M HNO3 (g) + M -KMnO4 and Na2C2O4 solutions were used in the reactions that took place in a back titration to determine the amount of H2O2 in a sample. Calculate the concentration of H2O2 in the sample (w / v) as% by making appropriate assumptions for the volumes and normality of all these solutions.4. If the amount of solvent was doubled to 200 grams, the solubility would: * O increase O decrease Ostay the same
- Use Boyle's law, P1V1 = P2V2, to calculate the volume, in mL, of the dry H2 at room pressure. Please enter your volumes using three decimal places and do not use scientific notation. partial pressure of the dry H2 in Torr = 734.7 torr moles of magnesium and moles of hydrogen gas produced in each trial - trial 1 - 0.003188 trial 2 - 0.003225 trial 3 - 0.003163100 B 80 D. 60 40 20 D] 0. 20 30 40 50 60 80 Temperature (C) 50 grams of substance Cis poured into water at 35 degrees.. How many grams won't dissolve? (first determine how many grams will dissolve. then subtract!) 70 10 Solubility (g in 100g water)Calculate the quantity of lime and soda required for softening one million litre of the following sample of water. If the purities of lime and soda are 80% and 85% respectively. The impurities are Silica mg/lit. CaSO4 = 68 mg/lit. MgCO3 = 884 mg/lit. CaCO3 = 120 mg/lit. 75 mg/lit. MgCl2 = 19 mg/lit. MgSO4 = 30 %3D %3D
- How many grams of MgCl2 in 30.00 mL of a 25.5 ppt solution ? (30.00 mL)(- mL а. 25.5 b. 100.0 С. 2 d. 30.00 f. 24 е. 6 i. 18.0 g. 3 h. 36 j. 1 k. 6.00 x 10-3 I. 3.60 х 10-2 m. 6.00 x 10-2 n. 5 О. 3.0 х 102 р. 1.80 х 10-2 9. 7.65 х 10-10 г. 2.63 S. 7.89 t. 5.26 и. 1012 V. 109 w. 106 х. 103 у. 101 z. 10You are checking the accuracy of a volumetric flask marked 10.00 mL. To calculate the volume of water contained in the flask, you first measure the mass of the empty flask and the mass of the flask filled with water and take the difference. Then, you correct for the buoyancy factor and divide by the density of the water. The result of 8 such measurements is given in the table. Measurement Volume (mL) 1 10.059 2 10.050 3. 10.009 4 10.062 Calculate the mean and the 95% confidence interval for these measurements. 10.025 6. 10.019 10.049 8. 10.020 ml. 10.036 mean: 10.021 mL 95% confidence interval: + IncorrectA bloodhound, with an acute sense of smell, sits at one end of a long, unventilated corridor.At the other end of the corridor a small amount of an aerosol is released containing the volatile, fragrant compounds: acetaldehyde (C2H4O) jasmine lactone (C10H16O2) acetoin (C4H8O2) hexyl acetate (C8H16O2) 1-octen-3-one (C8H14O) Rank the compounds in the chronological order they are detected by the hound. 1-octen-3-one acetoin jasmine lactone hexyl acetate acetaldehyde