2) A hot bar of lead with Ti Pb, Mpb = .6 kg, is dropped into an iron pot (mFe = .3 kg) that has mH20 = 1 kg of water in it. The initial temperature of the water and iron is T₁ = 20 °C. At equilibrium, the final temperature Tr =25 °C for each item. a) Write the expression for the heat LOST by the lead bar. This will be in terms of Ti Pb. Specific heat: CPb = 130 J/(kg °C). Write this as -(expression). Qlost = b) Calculate the heat gained by the water. Specific heat: CH20 = 4186 J/(kg °C). Get a number for this. QH2O = c) Calculate the heat gained by the iron. Specific heat: CFe = 450 J/(kg °C). Get a number for this. QFe = d) Set the expression for heat lost equal to the total heat gained, then solve for Ti pb. Ti Pb = °℃ e) The initial length of the hot lead bar is L₁ = .25 m. By how much does the length change when it reaches equilibrium? Coefficient of thermal expansion for lead a = 2.9 x 10-5 1/°C. Be careful with signs. AT = °C AL = m

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Chapter14: Heat And Heat Transfer Methods
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Thank you. Study guide final.
2) A hot bar of lead with Ti Pb, Mpb = .6 kg, is dropped into an iron pot (mFe = .3 kg)
that has mH20 = 1 kg of water in it. The initial temperature of the water and iron is
T₁ = 20 °C. At equilibrium, the final temperature Tf =25 °C for each item.
a) Write the expression for the heat LOST by the lead bar. This will be in terms of Ti Pb.
Specific heat: CPb = 130 J/(kg °C). Write this as -(expression).
Qlost =
b) Calculate the heat gained by the water. Specific heat: CH20 = 4186 J/(kg °C).
Get a number for this.
QH2O =
J
c) Calculate the heat gained by the iron. Specific heat: CFe = 450 J/(kg °C). ariables
Get a number for this.
what type
of process
* signs.
QFe =
d) Set the expression for heat lost equal to the total heat gained, then solve for Ti pb.
Ti Pb =
°℃
e) The initial length of the hot lead bar is L₁ = .25 m. By how much does the length
change when it reaches equilibrium? Coefficient of thermal expansion for lead
a = 2.9 x 10-5 1/°C. Be careful with signs. AT =
°C
AL =
m
Transcribed Image Text:2) A hot bar of lead with Ti Pb, Mpb = .6 kg, is dropped into an iron pot (mFe = .3 kg) that has mH20 = 1 kg of water in it. The initial temperature of the water and iron is T₁ = 20 °C. At equilibrium, the final temperature Tf =25 °C for each item. a) Write the expression for the heat LOST by the lead bar. This will be in terms of Ti Pb. Specific heat: CPb = 130 J/(kg °C). Write this as -(expression). Qlost = b) Calculate the heat gained by the water. Specific heat: CH20 = 4186 J/(kg °C). Get a number for this. QH2O = J c) Calculate the heat gained by the iron. Specific heat: CFe = 450 J/(kg °C). ariables Get a number for this. what type of process * signs. QFe = d) Set the expression for heat lost equal to the total heat gained, then solve for Ti pb. Ti Pb = °℃ e) The initial length of the hot lead bar is L₁ = .25 m. By how much does the length change when it reaches equilibrium? Coefficient of thermal expansion for lead a = 2.9 x 10-5 1/°C. Be careful with signs. AT = °C AL = m
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