10-240° V 102 120° V - ial a ia 1020° V -6+j8 N ibl b w ib −6+j8 C icl -6 + j8 Ω ic. Find the phase currents and line currents. (Positive magnitudes) digits) ia = ib = ic ial ibl ic = = = = (Phase angles between ±180°) (Round decimal answers to 2 2 ° A 4 4 4 2 PA 0 0 A ° A 0 O A ° A

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter7: Alternating Current, Power Distribution, And Voltage Systems
Section: Chapter Questions
Problem 7RQ
Question
10-240° V
102 120° V
-
ial
a
ia
1020° V
-6+j8 N
ibl
b
w
ib −6+j8
C
icl
-6 + j8 Ω
ic.
Find the phase currents and line currents.
(Positive magnitudes)
digits)
ia
=
ib =
ic
ial
ibl
ic
=
=
=
=
(Phase angles between ±180°) (Round decimal answers to 2
2
° A
4
4
4
2
PA
0
0
A
° A
0
O
A
° A
Transcribed Image Text:10-240° V 102 120° V - ial a ia 1020° V -6+j8 N ibl b w ib −6+j8 C icl -6 + j8 Ω ic. Find the phase currents and line currents. (Positive magnitudes) digits) ia = ib = ic ial ibl ic = = = = (Phase angles between ±180°) (Round decimal answers to 2 2 ° A 4 4 4 2 PA 0 0 A ° A 0 O A ° A
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