1.500 m - FBC +0.800TCD = 0 AB-FBC +0.600TCD = 0 15 N/m 0.800 m wing is a VALID equilibrium equation that can be obtained by summing force components? 0.800T CD = 0 0.600T CD = 0 wing is the correct expression resulting to the summation of moments about the x-axis? c(xo)-Tcp (0.6)0.8- Tcp (0.8)1.5 = 0 (0.8)-Tcp (0.6)0.8 = 0 +FBC (xo)-TCD (0.6)1.7 = 0 FBC (0.8)-TCD (0.6)0.8 = 0

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A bent rod ABC is supported by a pin and bracket at A and a cable CD. The weight of the bent rod is 15 N/m and is represented as distributed loads
along segments AB and BC.
A.
B.
C.
A.
1. Which of the following is a VALID equilibrium equation that can be obtained by summing force components?
EFX: FAX 0.800T CD = 0
EFx:FAx0.600T CD = 0
Fy: FAB FBC +0.800T CD = 0
D. Fy: FAY - FAB - FBC +0.600TCD = 0
B.
C.
◆
D.
◆
2. Which of the following is the correct expression resulting to the summation of moments about the x-axis?
FAB (ZO)- FBC (Xo) - Tcp(0.6)0.8- Tcp (0.8)1.5 = 0
FAB (ZO) + FBC (0.8) — Tcp (0.6)0.8 = 0
CAX + FAB (ZO) + FBC (xo) - TCD (0.6)1.7 = 0
CAX + FAB (Zo) + FBC (0.8)-TCD (0.6)0.8 = 0
0.800 m
57.5 N
47.5 N
15 N/m
21.8 N
7.19 N
1.500 m
◆
15 N/m
3. Which of the following best approximates the magnitude of the tension cable CD?
0.800 m
0.600 m
Transcribed Image Text:A bent rod ABC is supported by a pin and bracket at A and a cable CD. The weight of the bent rod is 15 N/m and is represented as distributed loads along segments AB and BC. A. B. C. A. 1. Which of the following is a VALID equilibrium equation that can be obtained by summing force components? EFX: FAX 0.800T CD = 0 EFx:FAx0.600T CD = 0 Fy: FAB FBC +0.800T CD = 0 D. Fy: FAY - FAB - FBC +0.600TCD = 0 B. C. ◆ D. ◆ 2. Which of the following is the correct expression resulting to the summation of moments about the x-axis? FAB (ZO)- FBC (Xo) - Tcp(0.6)0.8- Tcp (0.8)1.5 = 0 FAB (ZO) + FBC (0.8) — Tcp (0.6)0.8 = 0 CAX + FAB (ZO) + FBC (xo) - TCD (0.6)1.7 = 0 CAX + FAB (Zo) + FBC (0.8)-TCD (0.6)0.8 = 0 0.800 m 57.5 N 47.5 N 15 N/m 21.8 N 7.19 N 1.500 m ◆ 15 N/m 3. Which of the following best approximates the magnitude of the tension cable CD? 0.800 m 0.600 m
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