Pt1420 Unit 1 Assignment 1

47. The first container has 3 gallons 3 quarts 1 pint of diesel fuel, the second container has 5

56.78 g 60.33 g 56.78 g Initial measurement of water in the graduated cylinder 60.7 mL 62.3 mL 58.5 mL 57.2 mL Measurement of the graduated cylinder after metal #8 is added 67.3 mL 68.9 mL 65.3 mL 64.1 mL Volume 6.6 mL 6.6 mL 6.8 mL 6.9 mL Density 9.1 g/mL 8.6 g/mL 8.9 g/mL 8.2 g/mL IV. Calculations: 96.3 mL of water were in the Styrofoam cup.

The height of the water was measured in centimeters. The water height was measured using a ruler. The height of the water was recorded. Next, 19 mL of water were measured in a graduated cylinder. The 19 mL were poured into the bottle.

    For question (2) he again used mental math and came to the conclusion that it was 4 feet/ounce of water. His rationale was the same as for (1b), to get back down to the base height. At this point, it

Avaneesh: This is the cylinder vase. It has the greatest volume. To solve for the volume, you first find the area of the base, which is 25. Then you multiply that by the height, which is 40, to get 1000. After that, you do 1000 times pi, or 3.14, which is 3140. Finally label in cubic centimeters.

1. Planet X has a radius 3 times larger than the earth’s radius. How does this planet’s volume compare to Earth’s volume?

The process that we will use for the water in the cylinder is we will fill a 100 ml mark and pour the contents in a dry 100ml flask about twice and we will find the percent difference. And to find the percent difference we will have to use the equation right here. For the Cube we will weigh six stoppers but once at a time and compare the results so that we could find the average of all six cubes.

This again perfectly matches the predicted volume that was calculated for the conical section of the External Tank.

The volume of the cube was easy to calculate by measuring its length, width, and height to multiply them altogether. The cubical object provided for lab was measured 2.5 cm in all the measurements. It was multiplied (2.5 cm)³ to be 16 cm³ as the volume for the cube.

For the square prism I had to find make it hold 0.5KL which is the same as 0.5m3. I made the length of the prism 1.5 and the Hight 1.5 but I needed to find the width so I put it as A. The equation is 0.5m3 = 1.5x1.5xA so I took the a out and it equals 2.25. Which made the equation 0.5m3 =2.25xA. I then divide 2.25 by 2.25 and it cancelled out but what you do to one side you do to the other so 0.5 divided by 2.25 = 0.22 which gave me the answer for a. In The equation I can now put 0.22 for a and then it would be, 1.15x1.15x0.22 = 0.495cm. Now for the square prism its basically the exact same but with the different measurements. Volume=LxWxH, the length is 2.5cm, the width is 2.2cm but we don’t know what the hight is. We need to fill 0.5m3, I don’t know a so I take it out and then it becomes 2.5x2.2 and that equals 5.5, so then we can do 0.5=5.5xA and if I divide 5.5x5.5 it cancels out and if you divide one side you divide the other so it would be 0.5 divided by 5.5 = 0.09. So we can now go to the equation and but the answer in, 2.5x2.2x0.09=0.495. I think the square would be better for a water feature because it would fit better and not be as wide, it would also be a good size, if I chose the rectangular prism it would be a lot wider and longer but not that tall which is pretty annoying I chose the square because it would be the easiest to build and it would be easier to get the measurements but a circle would be super hard. For my part b I have chosen the square prism because it would fit better, be easier to get measurements and it would be taller that

A sample of an unknown gas (gas A) has a volume of 3.2 m3 at a temperature of 10 °C. Another sample of an unknown gas (gas B) has a volume of 4.5 m3 at a

The results were recorded and the data was analysed with the calculations produced and double checked. RESULTS AND CALCULATIONS: Size of the cube Surface area(cm^2) Volume(cm^3) Surface area to volume ratio 1cm 6 1 6:1 s2cm 24 8 3:1 3cm 54 27 2:1 Cube size(cm) Dimensions of coloured section remaining(cm) Volume of coloured section remaining(cm^3) Initial volume of the cube (cm^3) Volume diffused(cm^3) %volume diffused 1 .5 .52 1 .48 48 2 1.6 4.096 8 3.904 48.8 3 2.5 15.625 27 11.375 42.1

Inflow from the tank was calculated using the known internal dimensions of the tank, the % full reading, and the time step which the data was collected.

The method of finding the volume of a solid with a known cross section is, very straightforward. We will

4. A car travels 12 kms with a 4/5th filled tank. How far will the car travel with 1/3 filled tank?